What is the molarity of a solution that has 4.4 moles BaCl2 in 1.5 Liters of solution?
1 answer:
Answer:
2.9 M
Explanation:
Step 1: Given data
Moles of barium chloride (solute): 4.4 moles
Volume of solution: 1.5 liters
Step 2: Calculate the molarity of barium chloride in the solution
The molarity is a way to quantitatively express the concentration of a solute in a solution. The molarity is equal to the moles of solute divided by the volume, in liters, of solution.
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Answer:
Molarity = 0.5 M
Osmolarity = 0.5 x 2 = 1 Osmpl.
Molecules of Cl2 = 6.02 x / 4= 1.505 x
no. of molecules
Explanation:
If we add half mole in 1L volume than molarity will obviously be 0.5 M.
The osmolarity is molarity multiplies by number of dissociates of solute that for CaCl2 are 2. So, 2 x 0.5 = 1
Half will be molecules of Ca and half will be of Cl2 for 0.5M.