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irinina [24]
3 years ago
15

A) 4x + 1

Mathematics
1 answer:
tia_tia [17]3 years ago
6 0

Answer:

a) 4x + 1  expression

b) C = 15+ 3n  “it might be a Formula”

c) 3x + 4 = 13 equation

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Maria jogged 3 miles (I have picture)
vodka [1.7K]

Answer:

A=False

B=True

C=True

Step-by-step explanation:

4 0
3 years ago
I would really want for someone to help me, I need to turn this in tomorrow​
alukav5142 [94]

Answer:

x=0, y=0

x=8, y=4

Step-by-step explanation:

y= 1/2x

y=1/2(0)

y=0

y=1/2x

y=1/2(8)

y=4

3 0
3 years ago
PLEASE HELP AND HURRY
Inessa [10]

Answer:

4.75x=54+2.5x    x=24

Step-by-step explanation:

x=Number of games

4.75x=54+2.5x

Subtract 2.5x from both sides:

2.25x=54

Divide both sides by 2.25:

x=24

6 0
3 years ago
Help! How would I solve this trig identity?
NeTakaya

Using simpler trigonometric identities, the given identity was proven below.

<h3>How to solve the trigonometric identity?</h3>

Remember that:

sec(x) = \frac{1}{cos(x)} \\\\tan(x) = \frac{sin(x)}{cos(x)}

Then the identity can be rewritten as:

sec^4(x) - sen^2(x) = tan^4(x) + tan^2(x)\\\\\frac{1}{cos^4(x)} - \frac{1}{cos^2(x)}  = \frac{sin^4(x)}{cos^4(x)}  + \frac{sin^2(x)}{cos^2(x)} \\\\

Now we can multiply both sides by cos⁴(x) to get:

\frac{1}{cos^4(x)} - \frac{1}{cos^2(x)}  = \frac{sin^4(x)}{cos^4(x)}  + \frac{sin^2(x)}{cos^2(x)} \\\\\\\\cos^4(x)*(\frac{1}{cos^4(x)} - \frac{1}{cos^2(x)}) = cos^4(x)*( \frac{sin^4(x)}{cos^4(x)}  + \frac{sin^2(x)}{cos^2(x)})\\\\1 - cos^2(x) = sin^4(x) + cos^2(x)*sin^2(x)\\\\1 - cos^2(x) = sin^2(x)*sin^2(x) + cos^2(x)*sin^2(x)

Now we can use the identity:

sin²(x) + cos²(x) = 1

1 - cos^2(x) = sin^2(x)*(sin^2(x) + cos^2(x)) = sin^2(x)\\\\1 = sin^2(x) + cos^2(x) = 1

Thus, the identity was proven.

If you want to learn more about trigonometric identities:

brainly.com/question/7331447

#SPJ1

7 0
2 years ago
PLEASE HELP WITH THIS QUESTION! WILL MARK BRAINLIEST
sweet [91]
We know that
[scale factor ]=[real]/[drawing]
[real]=[drawing]*[scale factor ]

step 1
find the real values

if the base of Riley's drawing is 10 centimeters
 [real]=[drawing]*[scale factor ]--------> 10*3-------> 30 cm
the base of the triangular clock face is 30 cm

the  height of Riley's drawing is 15 centimeters 
[real]=[drawing]*[scale factor ]--------> 15*3-------> 45 cm
the  height of the triangular clock face is 30 cm

the  area of the triangular clock face is-----> 45*30/2-------> 675 cm²

the answer is the option C. 675 square centimeters
4 0
4 years ago
Read 2 more answers
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