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Artemon [7]
3 years ago
10

How are copper sulfate and copper sulfide different in term of the elements they contain

Chemistry
2 answers:
evablogger [386]3 years ago
8 0
Copper sulphide has the formula CuS  and copper sulphate is CuSO4

CuS  is a compound of sulphur and copper only  while CuSO4 has these 2 elements plus Oxygen 



Dovator [93]3 years ago
6 0

<u>Answer:</u> Copper sulfate has oxygen element in it while copper sulfide does not have.

<u>Explanation:</u>

Copper sulfate is formed by the combination of copper and sulfate ions. The chemical formula for this compound is CuSO_4

It is formed by the combination of atoms of copper, sulfur and oxygen elements.

Copper sulfide is formed by the combination of copper and sulfide ions. The chemical formula for this compound is CuS

It is formed by the combination of atoms of copper and sulfur elements.

Hence, copper sulfate has oxygen element in it while copper sulfide does not have.

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100.0 mL of 3.8M NaCN, the minimum lethal concentration of sodium cyanide in blood serum
9966 [12]

The given question is incomplete. The complete question is:

Calculate the number of moles and the mass of the solute in each of the following solution: 100.0 mL of 3.8 × 10−5 M NaCN, the minimum lethal concentration of sodium cyanide in blood serum

Answer: The number of moles and the mass of the solute are 0.38\times 10^{-5} and 18.62\times 10^{-5}g respectively

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.

Molarity=\frac{n\times 1000}{V_s}

where,

n = moles of solute

V_s = volume of solution in ml

3.8\times 10^{-5}M=\frac{n\times 1000}{100.0}

n=0.38\times 10^{-5}

n = moles of NaCN = \frac{\text {given mass}}{\text {Molar mass}}

0.38\times 10^{-5}=\frac{x}{49g/mol}

x=18.62\times 10^{-5}g

Thus the number of moles and the mass of the solute are 0.38\times 10^{-5} and 18.62\times 10^{-5}g respectively

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Have a great day! :)
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