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Yakvenalex [24]
1 year ago
15

Which contain a common ion that will shift the equilibrium system represented by the equation shown? Select all that apply. MgSO

4 Na2S HNO3 CaCl2.
Chemistry
1 answer:
inn [45]1 year ago
4 0

The compounds in the reaction that shifts the equilibrium with the common ion effect are \rm MgSO_2\;and\;HNO_3.

<h3>What is the common ion effect?</h3>

The equilibrium condition has an equal amount of reactant and products in the reaction.

The addition of ions same as product or reactant results in a change in the equilibrium of condition and shifts the equilibrium in opposite direction.

The given reaction is:

\rm H_2SO_4\;\rightleftharpoons 2H^+\;+\;SO_4^{2-}

The addition of sulfate and hydrogen ions shifts the equilibrium.

Thus, the compounds that shift the equilibrium for the reaction are \rm MgSO_2\;and\;HNO_3.

Learn more about equilibrium, here:

brainly.com/question/4289021

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8 0
3 years ago
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What volume of 0.25 M HCl would be needed to neutralize 45 mL of 0.12 M solution of Mg(OH)₂
dalvyx [7]

Answer:

0.38dm³

Explanation:

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4 0
2 years ago
Radioactive cobalt-60 is frequently used in treating cancer. It took 24 years for a 10 gram sample to decay to 0.625 grams. What
-BARSIC- [3]

Answer:

Half life is 6 years.

Explanation:

T½ = In2 / λ

Where λ = decay constant.

But N = No * e^-λt

Where N = final mass after a certain period of time

No = initial mass

T = time

N = 0.625g

No = 10g

t = 24 years

N = No* e^-λt

N / No = e^-λt

λ = -( 1 / t) In N / No (inverse of e is In. Check logarithmic rules)

λ = -(1 / 24) * In (0.625/10)

λ = -0.04167 * In(0.0625)

λ = -0.04167 * (-2.77)

λ = 0.1154

T½ = In2 / λ

T½ = 0.693 / 0.1154

T½ = 6.00 years.

The half life of radioactive cobalt-60 is 6 years

5 0
2 years ago
There are two common oxides of copper; one is 80% copper and the other is 89% copper by weight. Calculate the formula and name e
irakobra [83]

80% copper (Cu)

Cu: 80 :  63.546 = 1.259

O: 20 : 16 = 1.25

Cu:O = 1 : 1

the formula: CuO

89% copper (Cu)

Cu: 89 :  63.546 = 1.4

O: 11 : 16 = 0.6875

Cu:O = 2:1

the formula: Cu₂O

8 0
2 years ago
Your boss tells you that water at 68 F is flowing in a cooling tower loop at a rate of 600 gpm, in an 8-inch inside diameter pip
avanturin [10]

Explanation:

The volumetric flow rate of water will be as follows.

       q = 600 gpm \times \frac{0.000063 m^{3} s^{-1}}{1 gpm}

         = 0.0378 m^{3}/s&#10;

    Diameter = 8 in \times \frac{0.0254 m}{1 in}

                   = 0.2032 m

Relation between area and diameter is as follows.

           A = \frac{\pi}{4} \times D^{2}

               = \frac{3.14}{4} \times (0.2032 m)^{2}

               = 0.785 x 0.2032 x 0.2032

               = 0.0324 m^{2}

Also,     q = A × V

or,         V = \frac{q}{A}

                = \frac{0.0378 m^{3}/s}{0.0324 m^{2}}

                = 1.166 m/s

As, viscosity of water = 1 cP = 10^{-3} Pa-s

Density of water = 1000 kg/m^{3}

Therefore, we will calculate Reynolds number as follows.

 Reynolds number = \frac{D \times V \times density}{viscosity}

                                 = \frac{0.2032 m \times 1.166 m/s  \times 1000}{10^{-3}}  

                                = 236931.2

Hence, the flow will be turbulent in nature.

Thus, we can conclude that the Reynolds number is 236931.2 and flow is turbulent.

8 0
3 years ago
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