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3 years ago

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In a triangle the first angle is 10 degrees more than the second angle. The third angle is equal to the sum of first 2 angles .

Find the value of all three angles

1 answer:

timurjin [86]3 years ago

8 0

First angle= x+10
Second angle = x
Third angle = x+x+10 or 2x+10

X+10+x+2x +10=180
4x+20=180
Subtract 20 from both sides
4x=160
Divide both sides by 4
X=40
First angle =50
Second angle=40
Third angle =90

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Please help me:(*********

Licemer1 [7]

Answer:

x = 16

Step-by-step explanation:

I could be wrong so sorry in advance lol but this is what I did:

I made the equation 3x + 3 = ((7x-10)/2)

I divided the 2nd equation by 2 so that it would be the same length as RZ.

after that, I got: 3x + 3 = 3.5x - 5

from there, i did basic algebra to get the answer 16

hope this helps!

6 0

3 years ago

Please help me out :P

Veseljchak [2.6K]

cos θ = $\frac{-4\sqrt{65} }{65}$ , sin θ = $\frac{-7\sqrt{65} }{65}$ , cot θ = 4/7, sec θ = $\frac{-\sqrt{65} }{4}$ , cosec θ = $\frac{-\sqrt{65} }{7}$

<h3>What are trigonometric ratios?</h3>

Trigonometric Ratios are values of all the trigonometric functions based on the value of the ratio of sides in a right-angled triangle.

Sin θ: Opposite Side to θ/Hypotenuse

Tan θ: Opposite Side/Adjacent Side & Sin θ/Cos

Cos θ: Adjacent Side to θ/Hypotenuse

Sec θ: Hypotenuse/Adjacent Side & 1/cos θ

Analysis:

tan θ = opposite/adjacent = 7/4

opposite = 7, adjacent = 4.

we now look for the hypotenuse of the right angled triangle

hypotenuse = $\sqrt{7^{2} + 4^{2} }$ = $\sqrt{49+16}$ = $\sqrt{65}$

sin θ = opposite/ hyp = $\frac{7}{\sqrt{65} }$

Rationalize, $\frac{7}{\sqrt{65} }$ x $\frac{\sqrt{65} }{\sqrt{65} }$ = $\frac{7\sqrt{65} }{65}$

But θ is in the third quadrant(180 - 270) and in the third quadrant only tan and cot are positive others are negative.

Therefore, sin θ = - $\frac{7\sqrt{65} }{65}$

cos θ = adj/hyp = $\frac{4}{\sqrt{65} }$

By rationalizing and knowing that cos θ is negative, cos θ = - $\frac{-4\sqrt{65} }{65}$

cot θ = 1/tan θ = 1/7/4 = 4/7

sec θ = 1/cos θ = 1/ $\frac{4}{\sqrt{65} }$ = - $\frac{-\sqrt{65} }{4}$

cosec θ = 1/sin θ = 1/ $\frac{\sqrt{65} }{7}$ = $\frac{-\sqrt{65} }{7}$

Learn more about trigonometric ratios: brainly.com/question/24349828

#SPJ1

5 0

2 years ago

I really need help on this question offering 10 points if anybody could help me with this with proof I'd be very thankful

kozerog [31]

Answer:

n=15

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Plz need this answer ASAP!

notsponge [240]

<h2><u>Q</u><u>u</u><u>e</u><u>s</u><u>t</u><u>i</u><u>o</u><u>n</u>:-</h2>

If a = 6 - $\sqrt{35}$ , find the value of a² + $\frac{1}{a²}$

<h2><u>S</u><u>o</u><u>l</u><u>u</u><u>t</u><u>i</u><u>o</u><u>n</u>:-</h2>

a = 6 - $\sqrt{35}$ (Given)

Now, first of all we have to find the value of $\frac{1}{a}$ .

So, $\frac{1}{a}$ = $\frac{1}{6 \: - \: \sqrt{35}}$

$\frac{1}{a}$ = $\frac{6 \: + \sqrt{35}}{(6 \: - \: \sqrt{35})(6 \: + \: \sqrt{35})}$

$\frac{1}{a}$ = $\frac{6 \: + \sqrt{35}}{(6)² \: - \: (\sqrt{35})²}$

$\frac{1}{a}$ = $\frac{6 \: + \sqrt{35}}{36 \: - \: 35}$ $(\because \sqrt{35} \: × \: \sqrt{35} \: = \: 35)$

$\frac{1}{a}$ = $\frac{6 \: + \: \sqrt{35}}{1}$

$\frac{1}{a}$ = 6 + $\sqrt{35}$

Now, we have to find the value of a² + $\frac{1}{a²}$

So, a² + $\frac{1}{a²}$ = $(a \: + \frac{1}{a})²$ - 2.a. $\frac{1}{a}$

a² + $\frac{1}{a²}$ = $(6 \: - \sqrt{35} \: + \: 6 \: + \sqrt{35})²$ - 2

a² + $\frac{1}{a²}$ = (12)² - 2

a² + $\frac{1}{a²}$ = 144 - 2

a² + $\frac{1}{a²}$ = 142

The value of a² + $\frac{1}{a²}$ is <u>1</u><u>4</u><u>2</u>. [Answer]

7 0

3 years ago

Adelaide paid $35 for a manicure and gave the manicurist a 20% tip.

Nikolay [14]

That would be 35 + 0.20*35 = $42

7 0

3 years ago