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WARRIOR [948]
3 years ago
15

Suppose that all of the points on the circular dartboard shown are equally likely to be hit by a dart. If the radius of the shad

ed center circle is 1 and the radius of the entire dartboard is 4, what is the probability of throwing a dart and hitting the white part of the board? Round your answer to the nearest whole number.
Mathematics
2 answers:
jekas [21]3 years ago
6 0
This must double your chances so if i round the nearest whole number would be 8 any questions?
AfilCa [17]3 years ago
5 0

Answer: The probability of throwing a dart and hitting the white part of the board is 1.

Step-by-step explanation:

Since we have given that

Radius of shaded center circle = 1

So, Area of shaded center circle is given by

\pi r^2\\\\=\pi \times 1^2\\\\=\pi

Radius of entire dartboard = 4

Area of entire dartboard is given by

\pi\times 4^2\\\\=16\pi

Area of white part is given by

16\pi-\pi\\\\=15\pi

So, Probability of throwing a dart and hitting the white part of the board is given by

\dfrac{15\pi}{16\pi}\\\\\\=\dfrac{15}{16}=0.9375\approx 1

Hence, the probability of throwing a dart and hitting the white part of the board is 1.

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Step-by-step explanation:

We know that supplementary angles equal 180 degrees. So, set up the equations:

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Then, you just plug 89 back into ZB, and simplify:

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Can someone please help on this one?
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Answer:

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Step-by-step explanation:

should help!!!

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