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WARRIOR [948]
3 years ago
15

Suppose that all of the points on the circular dartboard shown are equally likely to be hit by a dart. If the radius of the shad

ed center circle is 1 and the radius of the entire dartboard is 4, what is the probability of throwing a dart and hitting the white part of the board? Round your answer to the nearest whole number.
Mathematics
2 answers:
jekas [21]3 years ago
6 0
This must double your chances so if i round the nearest whole number would be 8 any questions?
AfilCa [17]3 years ago
5 0

Answer: The probability of throwing a dart and hitting the white part of the board is 1.

Step-by-step explanation:

Since we have given that

Radius of shaded center circle = 1

So, Area of shaded center circle is given by

\pi r^2\\\\=\pi \times 1^2\\\\=\pi

Radius of entire dartboard = 4

Area of entire dartboard is given by

\pi\times 4^2\\\\=16\pi

Area of white part is given by

16\pi-\pi\\\\=15\pi

So, Probability of throwing a dart and hitting the white part of the board is given by

\dfrac{15\pi}{16\pi}\\\\\\=\dfrac{15}{16}=0.9375\approx 1

Hence, the probability of throwing a dart and hitting the white part of the board is 1.

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What substitution should be used to rewrite 6(x + 5)2 + 5(x + 5) – 4 = 0 as a quadratic equation? u = (x + 5) u = (x – 5) u = (x
Pachacha [2.7K]
6(x+5)² + 5(x+5)-4 = 0

(x+5)(x+5) = x(x+5)+5(x+5) = x² + 5x + 5x + 25 = x² + 10x + 25

6(x²+10x+25) + 5(x+5) - 4 = 0
6x² + 60x + 150 + 5x + 25 - 4 = 0
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5 0
3 years ago
This is the two that go together, but are separate questions
ira [324]

Answers:

Option 1)

6a + 8s = 102

14a + 4s = 150

each adult ticket costs 9 dollars

===================================================

Explanation:

6 adult tickets and 8 student tickets bring in $102, so that means 6a+8s = 102

14 adult tickets and 4 students tickets bring in $150, so 14a+4s = 150

The system of equations is

\begin{cases}6a+8s = 102\\14a+4s = 150\end{cases}

If we multiply both sides of the second equation by -2, we get this updated system

\begin{cases}6a+8s = 102\\-28a-8s = -300\end{cases}

Add the equations straight down

6a+(-28a) = -22a

8s+(-8s) = 0s = 0 ... the 's' terms go away

102+(-300) = -198

So we end up with the equation -22a = -198 and that solves to a = 9 after dividing both sides by -22.

Each adult ticket costs $9

If you want the value of s, then

6a+8s = 102

6(9)+8s = 102

54 + 8s = 102

8s = 102-54

8s = 48

s = 48/8

s = 6

Meaning each student ticket costs $6

Or you could use the other equation

14a+4s = 150

14(9)+4s = 150

126+4s = 150

4s = 150-126

4s = 24

s = 24/4

s = 6

We get the same value of s

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Answer:

Step-by-step explanation:

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