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Nana76 [90]
4 years ago
13

Unfortunately, no one buys your bracelets at a price of $10. this is a signal for you to _____. make more bracelets lower your p

rice increase your costs
Mathematics
2 answers:
Dmitriy789 [7]4 years ago
7 0

Answer:

Base price of one bracelet = $10

The problem which is being faced : No one is buying the bracelet at this cost

Now, to resolve this issue or problem a decision need to be taken in order to make people buy your bracelet.

The given options are :

Make more bracelets : Making more bracelets has no connection with the people not buying your bracelet. This would be effective in case there is a shortage for bracelets.

Lower your price : This could be effective as there is a possibility that people are finding it expensive to buy a brace;let at a base price of $10. So if you lower the base price of the bracelet, The chance are there that people will start buying your bracelets.

Increase your cost : Again there is no relation between increasing the cost and the the people not buying your bracelet. So, if you increase the base price of the bracelet then it will not have any effect on sale of the bracelets.

Hence, the most effective decision or person not buying a bracelet is a signal to lower the price of the bracelet.

tamaranim1 [39]4 years ago
3 0
I would think you would lower ur price. But I wouldn't  make the price so low so that it costs the same to produce them as it does to sell them, because then there would be no profit.
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Is 2/2 a improper fraction ?
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Answer:

no

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Find the point B on AC overline such that the ratio of AB to BC is 1:3
Degger [83]

Answer:

Step-by-step explanation:

The xxx-coordinate of BBB is 333 less than the xxx-coordinate of AAA, or 8 - 38−38, minus, 3.

The yyy-coordinate of BBB is 111 greater than the yyy-coordinate of AAA, or -8 + 1−8+1minus, 8, plus, 1.

The coordinates of BBB are (5, -7)(5,−7)left parenthesis, 5, comma, minus, 7, right parenthesis.

answer (5,-7)

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3 years ago
Reduce to lowest term. 2x^2- 18/x^2+4x-21​
Dovator [93]

Answer:

\frac{2(x+3)}{x+7}

Step-by-step explanation:

Given

\frac{2x^2-18}{x^2+4x-21} ← factorise numerator and denominator

2x² - 18 ( factor out 2 from each term )

= 2(x² - 9) ← difference of 2 squares

= 2(x - 3)(x + 3)

and

x² + 4x - 21 = (x + 7)(x - 3) , then

= \frac{2(x-3)(x+3)}{(x+7)(x-3)} ← cancel common factor (x - 3) on numerator/ denominator

= \frac{2(x+3)}{x+7}

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3 years ago
Evaluate the line integral, where c is the given curve. (x + 9y) dx + x2 dy, c c consists of line segments from (0, 0) to (9, 1)
viktelen [127]
\displaystyle\int_C(x+9y)\,\mathrm dx+x^2\,\mathrm dy=\int_C\langle x+9y,x^2\rangle\cdot\underbrace{\langle\mathrm dx,\mathrm dy\rangle}_{\mathrm d\mathbf r}

The first line segment can be parameterized by \mathbf r_1(t)=\langle0,0\rangle(1-t)+\langle9,1\rangle t=\langle9t,t\rangle with 0\le t\le1. Denote this first segment by C_1. Then

\displaystyle\int_{C_1}\langle x+9y,x^2\rangle\cdot\mathbf dr_1=\int_{t=0}^{t=1}\langle9t+9t,81t^2\rangle\cdot\langle9,1\rangle\,\mathrm dt
=\displaystyle\int_0^1(162t+81t^2)\,\mathrm dt
=108

The second line segment (C_2) can be described by \mathbf r_2(t)=\langle9,1\rangle(1-t)+\langle10,0\rangle t=\langle9+t,1-t\rangle, again with 0\le t\le1. Then

\displaystyle\int_{C_2}\langle x+9y,x^2\rangle\cdot\mathrm d\mathbf r_2=\int_{t=0}^{t=1}\langle9+t+9-9t,(9+t)^2\rangle\cdot\langle1,-1\rangle\,\mathrm dt
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Finally,

\displaystyle\int_C(x+9y)\,\mathrm dx+x^2\,\mathrm dy=108-\dfrac{229}3=\dfrac{95}3
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