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xz_007 [3.2K]
3 years ago
11

A bag contains 9 red, 6 green, 3 blue, and 2 yellow balls of the same size. A student chooses a colour and then draws a ball fro

m the bag. If she draws a ball of her choice of colour she wins, if not the teacher wins. Who do you think will be the winner after 24 rounds, the student or the teacher
Mathematics
1 answer:
Burka [1]3 years ago
5 0

Answer:

the teacher will win becasue there are less numbers of colors to choose from one of the catagories then there are in total.

Step-by-step explanation:

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Use the pythagorean theorem.
Dima020 [189]

Answer:

The answer for this question is 12yd

5 0
3 years ago
HELPPPPPPPPP 55 POINTS Isabel graphed the following system of equations.
Arturiano [62]

Answer:

1.  Substitute y = -3x +4 for y in the first equation

2.  Combine like terms and isolate x

3.  Substitute in x into the 2nd equation to get y

Step-by-step explanation:

1.  Substitute y = -3x +4 for y in the first equation

2x- (-3x+4) = 6

2.  Combine like terms

5x -4 = 6

5x -4 +4 = 6+4

5x=10  Divide by 5 to isolate x

5x/5 =10/5

x=2

3. Substitute in x into the 2nd equation to get y

y = -3x +4

y = -3(2) +4

y = -6+4

y=-2

(2,-2)

5 0
3 years ago
A box contains 24 transistors,4 of which are defective. If 4 are sold at random,find the following probabilities. i. Exactly 2 a
zavuch27 [327]

SOLUTION

This is a binomial probability. For i, we will apply the Binomial probability formula

i. Exactly 2 are defective

Using the formula, we have

\begin{gathered} P_x=^nC_x\left(p^x\right?\left(q^{n-x}\right) \\ Where\text{ } \\ P_x=binomial\text{ probability} \\ x=number\text{ of times for a specific outcome with n trials =2} \\ p=\text{ probability of success = }\frac{4}{24}=\frac{1}{6} \\ q=probability\text{ of failure =1-}\frac{1}{6}=\frac{5}{6} \\ ^nC_x=\text{ number of combinations = }^4C_2 \\ n=\text{ number of trials = 4} \end{gathered}

Note that I made the probability of being defective as the probability of success = p

and probability of none defective as probability of failure = q

Exactly 2 are defective becomes the binomial probability

\begin{gathered} P_x=^4C_2\times\lparen\frac{1}{6})^2\times\lparen\frac{5}{6})^{4-2} \\ P_x=6\times\frac{1}{36}\times\frac{25}{36} \\ P_x=\frac{25}{216} \\ =0.1157 \end{gathered}

Hence the answer is 0.1157

(ii) None is defective becomes

\begin{gathered} \lparen\frac{5}{6})^4=\frac{625}{1296} \\ =0.4823 \end{gathered}

hence the answer is 0.4823

(iii) All are defective

\begin{gathered} \lparen\frac{1}{6})^4=\frac{1}{1296} \\ =0.00077 \end{gathered}

(iv) At least one is defective

This is 1 - probability that none is defective

\begin{gathered} 1-\lparen\frac{5}{6})^4 \\ =1-\frac{625}{1296} \\ =\frac{671}{1296} \\ =0.5177 \end{gathered}

Hence the answer is 0.5177

3 0
10 months ago
Match the equations of the lines with their graphs.
xxMikexx [17]

Answer:

Step-by-step explanation:

1. y=2x-3

2. y=2x+3

3. y=-2x+3

4.  y=-2x-3

3 0
3 years ago
(3x - 2)³= <br>gives the solution pls.​
Nonamiya [84]

Answer:

27x^3 - 54x^2 + 36x - 8

Step-by-step explanation:

(3x - 2)^3

= (3x - 2) (3x - 2) (3x - 2)

= 27x^3 - 54x^2 + 36x - 8

Hope this helps :)

Let me know if there are any mistakes!!

5 0
3 years ago
Read 2 more answers
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