2 / 5 = 12 / 30
2 / 6 = 10 / 30
12 + 10 = 22
22 / 30 = 11 / 15
4 + 5 = 9
9 and 11 / 15 is your answer
To solve this, let us first imagine a smaller triangle
created by the head of Jim (A), the top of the lamp post (B), and somewhere on
the body of the lamp post which is directly perpendicular to the head of Jim
(C).
CB = 16 – 6 = 10 ft
AC = 4 ft
Calculate for angle B using tan function:
tan B = AC / CB
B = tan^-1 (4 / 10)
B = 21.8°
Now imagine a bigger triangle created by the tip of
shadow (D), the top of the lamp post (B), and the base of the lamp post (E).
BE = 16 ft
B = 21.8°
We can calculate for DE using tan function:
tan B = DE / BE
(16 ft) tan 21.8 = DE
DE = 6.4 ft
Since Jim is 4ft away from the base of the lamp post,
therefore the length of the shadow is:
6.4 ft – 4 ft
= 2.4 ft
Therefore the length of Jim’s shadow is 2.4 ft long
Answer:
D. 25a² +60a +36
Step-by-step explanation:
You have memorized the form ...
(p +q)² = p² +2pq +q²
so you can write down immediately the result for p=5a and q=6:
(5a)² +2(5a)(6) +6² = 25a² +60a +36
Answer:
It will take him <u>20 days</u> to read a 300-page book.
Step-by-step explanation:
Given:
Stephen read a 90-page book in 6 days.
If he continues reading at that rate.
Now, to find the time it will take him to read a 300-page book.
So, we solve using unitary method:
If, Stephen read 90 pages in 6 days.
So, Stephen read 1 page in =
days.
Thus, Stephen read 300 page in = ![\frac{6}{90} \times 300](https://tex.z-dn.net/?f=%5Cfrac%7B6%7D%7B90%7D%20%5Ctimes%20300)
![=\frac{1800}{90}](https://tex.z-dn.net/?f=%3D%5Cfrac%7B1800%7D%7B90%7D)
![=20\ days.](https://tex.z-dn.net/?f=%3D20%5C%20days.)
Therefore, it will take him 20 days to read a 300-page book.