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julsineya [31]
3 years ago
14

I am not sure if I did this right can someone explain this to me I am confused . Problem #1

Mathematics
1 answer:
-Dominant- [34]3 years ago
8 0
Yes, you did this right. 5 if the GCF of 15 and 5

all you have to do is find the GCF and then divide so you can get your new inside values with the gcf outside the parentheses. 
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I thought I had the right answer but apparently I don't. Help would be greatly appreciated. Thank you!
erma4kov [3.2K]

Answer:

1/36

Step-by-step explanation:

To get a sum of 2, both dice must roll a 1.

The probability of a 1 on the first die is 1/6.

The probability of a 1 on the second die is 1/6.

Therefore, the probability of rolling both 1s is:

P = 1/6 × 1/6 = 1/36

5 0
3 years ago
The diameter of Mercury is approximately 4.9×10^3 kilometers. The diameter of Earth is approximately 1.3×10^4 kilometers. About
JulijaS [17]
 \text {Number of times = } \dfrac{1.3 \times 10^4}{4.9 \times 10^3 }

\text {Number of times = }  \dfrac{1.3}{4.9} \times 10^{4-3}

\text {Number of times = }  0.27 \times 10

\text {Number of times = }  2.7
5 0
3 years ago
The slope intercept form of the equation of a line that passes through (-2,13) is y =5x-3what is the point slope form of the equ
Zigmanuir [339]

Answer:

y - 13 = 5(x + 2)

Step-by-step explanation:

The equation of a line in point- slope form is

y - b = m(x - a)

where m is the slope and (a, b) a point on the line

Given y = 5x - 3 in  slope- intercept form

with slope m = 5, then

m = 5 and (a, b) = (- 2, 13)

y - 13 = 5(x - (- 2)), that is

y - 13 = 5(x + 2) ← in point- slope form

6 0
3 years ago
Complete the point-slope equation of the line through (-8,-8) and (-7,9)
denis23 [38]

Step-by-step explanation:

point slope formula: y-y1=m(x-x1)

m= y2-y1/x2-x1

input numbers

so slope:

m=(9--8)/(-7--8)

(-)×(-)=+

(+)×(-)=(-)

so m=17/1

m=17

now point slope

y--8=17(x--8)

y+8=17x+136

to get y alone we have to use opposite operations

y and 8 are adding so we need to subtract on both sides

y+8-8=17x+136-8

y=17x+128

5 0
2 years ago
For which value of a does Limit of g(x) as x approaches alpha not exist?​
Hunter-Best [27]

The value of a where the Limit of g(x) as x approaches alpha not exist are -1 and 1

<h3>Limit of a function</h3>

The limit of a function is the limit of a function as x tends to a value.

From the given graph, you can see that the function g(x) goes large at the point where the arrows orange and purple point down from the x-coordinates -1 and 1.

Hence the value of a where the Limit of g(x) as x approaches alpha not exist are -1 and 1

Learn more on limit of a function here: brainly.com/question/23935467

#SPJ1

7 0
2 years ago
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