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2 years ago

How many solutions are there to 3x-10(x+2) =13-7x

Mathematics

1 answer:

Vaselesa [24]2 years ago

8 0

This is the following way to solve this problem:

3x-10(x+2)=13-7x

3x-10x-20=13-7x (multiply 10 times what's in the parentheses)

-7x-20=13-7x ( subtract 3x from -10x)

-7x-20-13=-7x ( since the 13 is positive, when we move it to the other

side, we change it's sign, so now we subtract 13 from 20

-7x-7=-7x

-7=-7x+7x ( we do the same thing we did above, now with the -7x)

-7=x

x=-7

Answer: x = -7

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: )

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Plot on a number line 4/7

Serjik [45]

Answer:

It will be over 4 and up 7. 4 spaces on the x axis, and 7 spaces on the y axis, the y axis is vertical. Think that the y has a v in it which stands for vertical

Step-by-step explanation:

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3 years ago

What is the value of x in the equation below?<br><br> 7x + 8 = -13

ivann1987 [24]

Answer:

x=-3

Step-by-step explanation:

7x=-13-8

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2 years ago

Read 2 more answers

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padilas [110]

Step-by-step explanation:

shape BCD is an isosceles triangle meaning the base angles will be the same.

CA is a straight line meaning that it is 180

the sum of angles in a triangle always is 180

180-36= 144

to find x you need to half 144 as it is the sum of the base angles of the isosceles triangle.

144/2= 72

x=72

the angle just below y is also 72.

as CA is a straight line,

180-72= 108 giving you the answer for y

y= 108

so to make the answer clear

x= 72

y= 108

hope that helped! :)

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6 0

2 years ago

Read 2 more answers

HELP ASAP

Andrei [34K]

Answer:

$radius = \sqrt{13}$ or $radius = 3.61$

Step-by-step explanation:

Given

Points:

A(-3,2) and B(-2,3)

Required

Determine the radius of the circle

First, we have to determine the center of the circle;

Since the circle has its center on the x axis; the coordinates of the center is;

$Center = (x,0)$

Next is to determine the value of x through the formula of radius;

$radius = \sqrt{(x_1 - x)^2 + (y_1 - y)^2} = \sqrt{(x_2 - x)^2 + (y_2 - y)^2}$

Considering the given points

$A(x_1,y_1) = A(-3,2)$

$B(x_2,y_2) = B(-2,3)$

$Center(x,y) =Center (x,0)$

Substitute values for $x,y,x_1,y_1,x_2,y_2$ in the above formula

We have:

$\sqrt{(-3 - x)^2 + (2 - 0)^2} = \sqrt{(-2 - x)^2 + (3 - 0)^2}$

Evaluate the brackets

$\sqrt{(-(3 + x))^2 + 2^2} = \sqrt{(-(2 + x))^2 + 3 ^2}$

$\sqrt{(-(3 + x))^2 + 4} = \sqrt{(-(2 + x))^2 + 9}$

Eva;uate all squares

$\sqrt{(-(3 + x))(-(3 + x)) + 4} = \sqrt{(-(2 + x))(-(2 + x)) + 9}$

$\sqrt{(3 + x)(3 + x) + 4} = \sqrt{(2 + x)(2 + x) + 9}$

Take square of both sides

$(3 + x)(3 + x) + 4 = (2 + x)(2 + x) + 9$

Evaluate the brackets

$3(3 + x) +x(3 + x) + 4 = 2(2 + x) +x(2 + x) + 9$

$9 + 3x +3x + x^2 + 4 = 4 + 2x +2x + x^2 + 9$

$9 + 6x + x^2 + 4 = 4 + 4x + x^2 + 9$

Collect Like Terms

$6x -4x + x^2 -x^2 = 4 -4 + 9 - 9$

$2x = 0$

Divide both sides by 2

$x = 0$

This implies the the center of the circle is

$Center = (x,0)$

Substitute 0 for x

$Center = (0,0)$

Substitute 0 for x and y in any of the radius formula

$radius = \sqrt{(x_1 - 0)^2 + (y_1 - 0)^2}$

$radius = \sqrt{(x_1)^2 + (y_1)^2}$

Considering that we used x1 and y1;

In this case we have that; $A(x_1,y_1) = A(-3,2)$

Substitute -3 for x1 and 2 for y1

$radius = \sqrt{(-3)^2 + (2)^2}$

$radius = \sqrt{13}$

$radius = 3.61$ ---<em>Approximated</em>

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3 years ago

Sam is a waiter at a local restaurant where he earns wages of $7per hour. Sam figures that he also earns about $5 in tips for ea

Mnenie [13.5K]

There aren't any functions listed to choose from, but it should look something like the following:

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substitute 6 hours in for h

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E= 42 + 5n OR E= 5n + 42

Hope this helps! :)

8 0

3 years ago