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VladimirAG [237]
3 years ago
11

Am i doing this right????

Mathematics
1 answer:
Anna35 [415]3 years ago
3 0
You are going in the right direction. For the distance of ST I get √136
√(-5-1)² + (6+4)² =
√(-6)² + (10²) =
√ 36 + 100 =
√136

√34² + √136² =√170²
34 + 136 = 170
170 = 170
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Answer:

E=5.544*10^{-26} J

Step-by-step explanation:

The equation for photon energy is given by:

E=hf

Where:

h=Planck\hspace{3}constant=6.6*10^{-34} \\f=Frequency\hspace{3}of\hspace{3}the\hspace{3}wave=84000000Hz

This equation telling us that the higher the frequency of the photon, the greater its energy. And the longer the photon wavelength, the lower its energy.

So, replacing the data provided in the previous equation:

E=(6.6*10^{-34} )*(84000000)=5.544*10^{-26} J

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100 - (76 + 14) = 100 - 90 = 10 <== numbers equal to 15
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Please answer this question​
Y_Kistochka [10]

\bold{\huge{\underline{ Solution }}}

<u>Before </u><u>answering </u><u>the </u><u>given </u><u>question</u><u>, </u><u>you </u><u>should </u><u>know </u><u>the </u><u>difference </u><u>between </u><u>polygon </u><u>and </u><u>regular </u><u>polygon</u><u>. </u>

  • Polygon :- It is closed figure constitute of straight line having different measurements and also having varies angles.
  • Regular polygon :- It is also a closed figure constitute of straight lines which having equal measuresment and all the angles of the given polygon are equal .

<u>There </u><u>are </u><u>different </u><u>types </u><u>of </u><u>polygon </u><u>based </u><u>on </u><u>the </u><u>sides </u><u>:</u><u>-</u>

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<h3><u>Let's </u><u>Begin </u><u>:</u><u>-</u></h3>

I have thought to make a 4 side polygon that is quadrilateral.

<u>Steps </u><u>of </u><u>construction </u><u>:</u><u>-</u><u> </u>

  • Step - 1 :- Draw a 5 cm line AB horizontally
  • Step - 2 :- Then , From a point B, Draw a Vertical line of 5 cm and named it BC
  • Step - 3 :- Then, From a point C, Draw a horizontal line of 5 cm and named it CD
  • Step - 4 :- Now, join the line AD
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<u>Result </u><u>:</u><u>-</u><u> </u> All the angles are equal that is 90° each.

<u>Conclusion </u><u>:</u><u>-</u><u> </u> The above figure is square as it is having equal sides and angles.

<h3><u>Now</u><u>, </u><u>we </u><u>have </u><u>to </u><u>find </u><u>the </u><u>sum </u><u>of </u><u>the</u><u> </u><u>angles</u><u> </u><u>of </u><u>the </u><u>polygon </u><u>:</u><u>-</u></h3>

<u>Here</u><u>, </u><u> </u>

  • All angles are equal in measure 90°

<u>Therefore</u><u>, </u>

The sum of the angles of the given polygon

\sf{ = 90{\degree} + 90{\degree} + 90{\degree} + 90{\degree} }

\sf{ = 180{\degree} + 90{\degree} + 90{\degree} }

\sf{ = 270{\degree} + 90{\degree} }

\sf{ = 360{\degree} }

Hence, The sum of the angles of the above polygon is 360° .

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