Answer:
B. There is not sufficient evidence at the 0.02 level of significance that the new technique reduces training time.
Step-by-step explanation:
We are given that using traditional methods it takes 107 hours to receive an advanced flying license.
A researcher believes the new technique may reduce training time and decides to perform a hypothesis test.
Let 
= <u><em>average training time to receive an advanced flying license</em></u>
So, Null hypothesis, 
: 
107 hours {means that the new technique doesn't reduce training time}
Alternate Hypothesis, 
: < 107 hours {means that the new technique may reduce training time}
Now, it is stated that after performing the test on 50 students, the researcher decides to reject the null hypothesis at a 0.10 level of significance.
As we know that if the test statistics value is rejected at a 10% level of significance, then it must not be rejected at the 0.02 level of significance.
This means that there is not sufficient evidence at the 0.02 level of significance that the new technique reduces training time because our null hypothesis has not been rejected.
15,000,000,000 = 15 × 10⁹
15 × 10⁹ - 5.8 × 10⁹ = 9.2 × 10⁹ m
Answer: C. 9.2 × 10⁹ m
Answer:
The proportion of students whose height are lower than Darnell's height is 71.57%
Step-by-step explanation:
The complete question is:
A set of middle school student heights are normally distributed with a mean of 150 centimeters and a standard deviation of 20 centimeters. Darnel is a middle school student with a height of 161.4cm.
What proportion of proportion of students height are lower than Darnell's height.
Answer:
We first calculate the z-score corresponding to Darnell's height using:
We substitute x=161.4 , 
, and 
to get:
From the normal distribution table, we read 0.5 under 7.
The corresponding area is 0.7157
Therefore the proportion of students whose height are lower than Darnell's height is 71.57%
