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Dafna11 [192]
3 years ago
9

Uestion 1 how many grams of disodium ethylenediaminetetraacetate (molar mass = 372.24 g/mol) required to prepare 500. ml of a 0.

0100 m solution
Chemistry
1 answer:
Jlenok [28]3 years ago
6 0
The solution is as follows:

Important data:
*0.01 M solution = 0.01 moles <span>disodium ethylenediaminetetraacetate/ L solution
*1 L = 1000 mL
*Molar mass = 372/24 g/mol

Stoichiometric calculation:
0.01 mol/L * (1 L/1000 mL) * 500 mL * </span><span>372.24 g/mol = 1.8612 g

Therefore, you would need 1.8612 grams of </span>disodium ethylenediaminetetraacetate.
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