Question

Uestion 1 how many grams of disodium ethylenediaminetetraacetate (molar mass = 372.24 g/mol) required to prepare 500. ml of a 0.0100 m solution

Answer 1

The solution is as follows:

Important data:
*0.01 M solution = 0.01 moles disodium ethylenediaminetetraacetate/ L solution
*1 L = 1000 mL
*Molar mass = 372/24 g/mol

Stoichiometric calculation:
0.01 mol/L * (1 L/1000 mL) * 500 mL * 372.24 g/mol = 1.8612 g

Therefore, you would need 1.8612 grams of disodium ethylenediaminetetraacetate.