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mihalych1998 [28]
2 years ago
12

During which change of state would the volume of a substance increase the most?

Chemistry
1 answer:
Mademuasel [1]2 years ago
8 0

Answer:

sublimation

Explanation:

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What is the empirical formula of a compound composed of 3.25% hydrogen ( H ), 19.36% carbon ( C ), and 77.39% oxygen ( O ) by ma
Montano1993 [528]

Answer:

The answer to your question is C₂HO₃

Explanation:

Data

Hydrogen = 3.25%

Carbon = 19.36%

Oxygen = 77.39%

Process

1.- Write the percent as grams

Hydrogen = 3.25 g

Carbon = 19.36 g

Oxygen = 77.39 g

2.- Convert the grams to moles

                     1 g of H ----------------- 1 mol

                   3,25 g of H -------------  x

                     x = (3.25 x 1) / 1

                     x = 3.25 moles

                    12 g of C ---------------- 1 mol

                     19.36 g of C ----------  x

                     x = (19.36 x 1) / 12

                     x = 1.61 moles

                     16g of O --------------- 1 mol

                     77.39 g of O ---------  x

                      x = (77.39 x 1)/16

                      x = 4.83

3.- Divide by the lowest number of moles

Carbon = 3.25/1.61 = 2

Hydrogen = 1.61/1.61 = 1

Oxygen = 4.83/1.61 = 3

4.- Write the empirical formula

                        C₂HO₃

4 0
3 years ago
Of the colors on the visible light spectrum, which one has the longest wavelength, lowest frequency, and lowest energy?
Elenna [48]

Answer:

Red

Explanation:

Violet - shortest wavelength, around 400-420 nanometers with highest frequency. They carry the most energy.

Indigo - 420 - 440 nm

Blue - 440 - 490 nm

Green - 490 - 570 nm

Yellow - 570 - 585 nm

Orange - 585 - 620 nm

Red - longest wavelength, at around 620 - 780 nanometers with lowest frequency and least amount of energy

Therefore, <em>red </em>is the answer you're looking for.

I hope this helps and that you have a great day! :)

5 0
2 years ago
Consider the reaction. mc014-1.jpg How many grams of methane should be burned in an excess of oxygen at STP to obtain 5.6 L of c
garri49 [273]
The reaction for the combustion of methane can be expressed as follows.
                           CH4 + 2O2 --> CO2 + 2H2O
We solve first for the amount of carbon dioxide in moles by dividing the given volume by 22.4L which is the volume of 1 mole of gas at STP.
                            moles of CO2 = (5.6 L) / (22.4 L/1 mole)
                             moles of CO2 = 0.25 moles
Then, we can see that every mole of carbon dioxide will need 1 mole of methane
                              moles methane = (0.25 moles CO2) x (1 moles O2/1 mole CO2)
                                                    = 0.25 moles CH4
Then, multiply this by the molar mass of methane which is 16 g/mole. Thus, the answer is 4 grams methane. 
5 0
3 years ago
Read 2 more answers
Why are hydrogen bonds important for the properties of water?
zavuch27 [327]
Water has the special type of attraction called Hydrogen bonding.  The bonds between the Hydrogen and the Oxygen in each water molecule make a super dipole because the Oxygen atom is way more electronegative than the hydrogen atom.  These OH bonds can then be attracted to other H2O molecules.  If you have ever poured water up to the brim and there is  little bit of water that is poking above the top, hydrogen bonding keeps those water molecules from spilling
5 0
3 years ago
2.00 moles of an ideal gas was found to occupy a volume of 17.4L at a pressure of 3.00 atm and at a temperature of 45 C. Calulat
lidiya [134]

Answer:

0.082 atm L mol^{-1} K^{-1}

Explanation:

The pressure, the volume and the temperature of an ideal gas are related to each other by the equation of state:

pV=nRT

where

p is the pressure of the gas

V is the volume of the gas

n is the number of moles

R is the gas constant

T is the absolute temperature

For the gas in this problem:

n = 2.00 mol is the number of moles

V = 17.4 L is the gas volume

p = 3.00 atm is the gas pressure

T=45C+273=318 K is the absolute temperature

Solving for R, we find the gas constant:

R=\frac{pV}{nT}=\frac{(3.00)(17.4)}{(2.00)(318)}=0.082 atm L mol^{-1} K^{-1}

5 0
3 years ago
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