Answer:
The stationary phase in chromatography experiment is paper.
Explanation:
In chromatography experiment, the stationary phase is defined as the fixed substance that is necessary to start chromatography. In our case, this fixed substance is paper, so that makes paper our stationary phase.
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Answer:
A, B & C form the vertices of a triangle.
∠ CAB = 90°, ∠ ABC = 73° and AB = 9.4.
Calculate the length of BC rounded to 3 SF
Answer:
Chemical (you should mark me brainliest lol)
Explanation:
Chemical properties can only be measured by changing substances chemical identity.
Answer:
3.47 × 10²³ C atoms
Solution:
Data Given:
Mass of Diamond = 48 mg = 0.048 g
M.Mass of Diamond = 12.01 g.mol⁻¹ (as it is purely Carbon)
Step 1: Calculate Moles of Diamond as,
Moles = Mass ÷ M.Mass
Putting values,
Moles = 0.048 g ÷ 12.01 g.mol⁻¹
Moles = 0.576 mol
Step 2: Calculate number of Carbon atoms,
As 1 mole of any substance contains 6.022 × 10²³ particles (Avogadro's Number) then the relation for Moles and Number of Carbon atoms can be written as,
Moles = Number of C Atoms ÷ 6.022 × 10²³ Atoms.mol⁻¹
Solving for Number of C atoms,
Number of C atoms = Moles × 6.022 × 10²³ Atoms.mol⁻¹
Putting value of moles,
Number of C atoms = 0.576 mol × 6.022 × 10²³ Atoms.mol⁻¹
Number of C atoms = 3.47 × 10²³ C atoms