All categories

3 years ago

Continental air masses form over water and maritime air masses form over land.

Chemistry

1 answer:

maksim [4K]3 years ago

3 0

False, I'm assuming, due to their names. Continents are landmasses and maritime is always to do with the sea

You might be interested in

In the periodic table below, shade all the elements for which the neutral atom has a valence electron configuration of ns2np3 ,

Lorico [155]

Answer is: chemical elements in group 15 of the periodic table have neutral atom with a valence electron configuration of ns²np³.
Nitrogen: [He] 2s² 2p³.
Phosphorus: [Ne] 3s² 3p³.
Arsenic: [Ar] 3d¹⁰ 4s² 4p³.
Bismuth: [Xe] 4f¹⁴ 5d¹⁰ 6s² 6p³.
Moscovium: predicted [Rn] 5f¹⁴ 6d¹⁰ 7s² 7p³.
These elements have 5 valence electrons.

5 0

4 years ago

What happens to the force needed to stretch a elastic object?

musickatia [10]

Explanation:

it increases to stretch it farther

3 0

3 years ago

What happens when you mix hydrogine, potassium and sodium

Anika [276]

Answer:

Explanation:

As the piece of metal skitters across the surface of the water in a beaker and — particularly in the case of potassium — it appears to catch fire, it is not obvious that the explanation for both phenomena lies in the production of hydrogen gas.

3 0

2 years ago

Identify the reactants in this reaction.

vovangra [49]

Explanation:

When mixed together, baking soda and vinegar undergo a chemical reaction. Carbon dioxide, water, and sodium acetate are formed during the reaction.

7 0

3 years ago

Read 2 more answers

Excess oxygen gas (O2) reacts with 244g of Iron (Fe) to produce 332 g of Fe2O3. What is the percent yield?

Andru [333]

Answer:

95.15%

Explanation:

To calculate the percent yield, we need the following formula:

$\% yield=\dfrac{actual yield}{theoreticalyield}\times100\%$

Solving for the theoretical yied, you need to predict how much of the product will be produced if we USE up the given.

Our given is 224g of Fe and we to get the theoretical yield, we need to figure out how much product will Fe produce supposing that we use up all the reactant.

First thing we do is get the balance equation of this chemical reaction:

4Fe + 3O₂ → 2Fe₂O₃

We get the ratio between Fe and the the product, Fe₂O₃

$\dfrac{4moles of Fe}{2molesofFe_{2}O_{3}}=\dfrac{2moles of Fe}{1moleofFe_{2}O_{3}}$

This basically means that we need 2 moles of Fe to produce 1 mole of Fe₂O₃. We'll use this later.

Now we let's use our given:

We need to first convert our given to moles. To do this, we need to determine how many grams there are of the reactant for every mole. We need to first get the atomic mass of the elements involved in the substance:

Iron(1)

Fe = 55.845(1) = 55.845g/mole(1)

Then we use this to convert grams to moles

$244g\times\dfrac{1mole}{55.845g}=4.369moles$

This means that there are 4.396moles of Fe in 244g of Fe.

This we will use to see how many moles of product we can produce given the moles of reactant by using the reactant:rproduct ratio.

$4.369moles of Fe\times\dfrac{1moleofFe_{2}O_{3}}{2molesofFe}=2.185 moles of Fe_{2}O_{3}$

So given 4.693 moles of Fe we can produce 2.185 moles of Fe₂O₃

The next step is to get how many grams of product there are given our calculation. We do this again by getting how many grams of Fe₂O₃ there are in 1 mole.

Fe(2) O(3)

Fe₂O₃=55.845(2) + 15.999(3)

= 111.69 + 47.997 =159.687g/mol

We then use this to solve for how many grams of product there are in 2.185 moles.

$2.185moles\times\dfrac{159.687g}{1mole}=348.92g$

This is our theoretical yield 348.92g of Fe₂O₃.

We can finally use our percent yield equation. Our actual yield is given by the probelm, 332g of Fe₂O₃ and we solved for our theoretical yield which is 348.92g of Fe₂O₃. We plug this in our formula and solve.

$\%yield=\dfrac{actual yield}{theoreticalyield}\times100\%$

$\%yield=\dfrac{332gofFe_{2}O_{3}}{348gofFe_{2}O_{3}}\times100\%=95.15\%$

So the answer is 95.15%

3 0

3 years ago