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-Dominant- [34]
2 years ago
7

How many orbitals are in 5dx2​

Chemistry
1 answer:
meriva2 years ago
6 0
An atom can have five 5d orbitals. In fact, a d sublevels of an electron shell have five orbitals regardless of whether there are enough electrons to...
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What volumes of 0.200 M HCOOH and 2.00 M NaOH would make 500. mL of a buffer with the same pH as one made from 475 mL of 0.200 M
Fed [463]

<u>36 ml of NaOh and</u><u> 464 ml</u><u> of </u><u>HCOOH</u><u> would be enough to form 500 ml of a buffer with the same pH as the buffer made with </u><u>benzoic acid </u><u>and NaOH.</u>

What is benzoic acid found in?

  • Some natural sources of benzoic acid include: ​Fruits:​ Apricots, prunes, berries, cranberries, peaches, kiwi, bananas, watermelon, pineapple, oranges.
  • ​Spices:​ Cinnamon, cloves, allspice, cayenne pepper, mustard seeds, thyme, turmeric, coriander.

Calculate the amount of moles in NaOH and benzoic acid. This calculation is done by multiplying molarity by volume.

Amount of moles of NaOH -2 × 0.025 =  0.05 mol

Amount of moles of benzoic acid 2 × 0.475 = 0.095 mol

In this case, we can calculate the pH produced by the buffer of these two reagents, as follows

pH = pKa + log\frac{base}{acid}

4.2 + log\frac{0.05}{0.045} = 4.245

We must repeat this calculation, with the values shown for HCOOH and NaOH. In this case, we can calculate as follows

pH = pKa + log\frac{base}{acid}

4.245 = 3.75 + log\frac{base}{acid}

log\frac{base}{acid} = 0.5

\frac{base}{acid} = 3.162

Now we must solve the equation above. This will be done using the following values

\frac{2(0.5 - x)}{0.2x - 2(0.5 - x)} = 0.464 L

With these values, we can calculate the volumes of NaOH and HCOOH needed to make the buffer.

NaOH volume

( 0.5 - 0.464)L

0.036L .................... 36ml

HCOOH volume

500 - 36 = 464mL

Learn more about benzoic acid

brainly.com/question/24052816

#SPJ4

3 0
2 years ago
Given that 7.25 moles of carbon monoxide gas are present in a container of volume 11.90 L, what is the pressure of the gas (in a
d1i1m1o1n [39]

Answer:17.955atm

Explanation:Pv=nrt

P= nrt/v

P= 7.25*0.08205*360/11.90

P= 214.1505/11.90

P=17.995atm

6 0
3 years ago
(HELPP NEEEDED NOW) Which example shows competition between members of the same population in a community? A pride of lions work
klio [65]

Answer:

C

Explanation:

A pride of lions working together suggests the opposite of competition.

Same comment about the water buffalo.

The answer is C. If the territory is invaded and the two males clash, that's competition.

A Cheetah is not part of the Lion's Pride.

7 0
3 years ago
How many grams of ammonia gas can be formed from 54.1 g of hydrogen gas
Murrr4er [49]

Answer:

304.19 g

Explanation:

M(H2) = 2*1 = 2 g/mol

54.1 g H2 * 1 mol H2/2gH2 = 27.05 mol H2        

                                   3H2 + N2 ------> 2NH3

from reaction             3 mol                  2 mol

given                   27.05 mol                 x mol

x = 27.05*2/3 = 18.03 mol NH3

M(NH3) = 14 +3*1 = 17 g/mol

18.03 mol NH3 * 17 g NH3/ 1 mol NH3 ≈ 307 g

Closeet answer is 304.19 g.

4 0
3 years ago
How many significant figures are in 340500
vovikov84 [41]
There are 4 significant digits: 3405.
4 0
3 years ago
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