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Scilla [17]
3 years ago
6

Multiply: 4x ^3sqrt 4x^2 (2 ^3sqrt 32x^2 * x ^3sqrt 2x)

Mathematics
1 answer:
Alik [6]3 years ago
7 0
I am sorry it’s to hard I tried this about 5x sorry bro
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In HIJ, the measure of J=90°, IJ = 5.6 feet, and JH = 4.7 feet. Find the measure of
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Step-by-step explanation: gave up on delta math

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(2x^2/4x-8)×(x-6)(x+1)/x^5
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\frac{2x^{2}}{4x - 8} * \frac{(x - 6)(x + 1)}{x^{5}} = \frac{2}{4x - 8} * \frac{x^{2} - 5x - 6}{x^{3}} = \frac{2x^{2} - 10x - 12}{4x^{4} - 8x^{3}}
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Find the exact value of tan ^-1 (-root of 3)<br> Write your answer in radians in terms of n.
mamaluj [8]

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If you take a look at the important angles, you will notice that the arc is minus 60 degrees which equals -1.04716755 radians.

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3 years ago
Find the standard deviation, σ, for the binomial distribution which has the stated values of n and p. round your answer to the n
True [87]
The standard deviation is 19.91.

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4 0
3 years ago
Let V be the volume of the solid obtained by rotating about the y-axis the region bounded y = sqrt(25x) and y = x^2/25. Find V b
Westkost [7]

Explanation:

Let f(x) = \sqrt{25x} and g(x) = \frac{x^2}{25}. The differential volume dV of the cylindrical shells is given by

dV = 2\pi x[f(x) - g(x)]dx

Integrating this expression, we get

\displaystyle V = 2\pi\int{x[f(x) - g(x)]}dx

To determine the limits of integration, we equate the two functions to find their solutions and thus the limits:

\sqrt{25x} = \dfrac{x^2}{25}

We can clearly see that x = 0 is one of the solutions. For the other solution/limit, let's solve for x by first taking the square of the equation above:

25x = \dfrac{x^4}{(25)^2} \Rightarrow \dfrac{x^3}{(25)^3} = 1

or

x^3 =(25)^3 \Rightarrow x = \pm25

Since we are rotating the functions around the y-axis, we are going to use the x = 25 solution as one of the limits. So the expression for the volume of revolution around the y-axis is

\displaystyle V = 2\pi\int_0^{25}{x\left(\sqrt{25x} - \frac{x^2}{25}\right)}dx

\displaystyle\:\:\:\:=10\pi\int_0^{25}{x^{3/2}}dx - \frac{2\pi}{25}\int_0^{25}{x^3}dx

\:\:\:\:=\left(4\pi x^{5/2} - \dfrac{\pi}{50}x^4\right)_0^{25}

\:\:\:\:=4\pi(3125) - \pi(7812.5) = 14726.2

4 0
3 years ago
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