How does the graph of y = sec(x + 3) – 7 compare with the graph of y = sec(x)?

Mathematics

2 answers:

jarptica [38.1K]3 years ago

5 0

Answer:

Step-by-step explanation:

Alla [95]3 years ago

3 0

Answer:

The function y = sec(x) shifted 3 units left and 7 units down .

Step-by-step explanation:

Given the function: y = sec(x)

If k is any positive real number, then the graph of f(x) - k is the graph of y = f(x) shifted downward k units.

If p is a positive real number, then the graph of f(x+p) is the graph of y=f(x) shifted to the left p units.

The function $y = \sec(x+3)-7$ comes from the base function y= sec(x).

Since 3 is added added on the inside, this is a horizontal shift Left 3 unit, and since 7 is subtracted on the outside, this is a vertical shift down 7 units.

Therefore, the transformation on the given function is shifted 3 units left and 7 units down

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The equation v(x)=32500(0.92)^x how much more is the truck worth after two years than after three years

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Answer:

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Step-by-step explanation:

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