How does the graph of y = sec(x + 3) – 7 compare with the graph of y = sec(x)?
2 answers:
Answer:
The function y = sec(x) shifted 3 units left and 7 units down .
Step-by-step explanation:
Given the function: y = sec(x)
- If k is any positive real number, then the graph of f(x) - k is the graph of y = f(x) shifted downward k units.
- If p is a positive real number, then the graph of f(x+p) is the graph of y=f(x) shifted to the left p units.
The function comes from the base function y= sec(x).
Since 3 is added added on the inside, this is a horizontal shift Left 3 unit, and since 7 is subtracted on the outside, this is a vertical shift down 7 units.
Therefore, the transformation on the given function is shifted 3 units left and 7 units down
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Step-by-step explanation:
(x+2)^2 + (y-3)^3 = 4
the #'s in the () are your center coordinates
Do the opposite signs to get (-2, 3)
Then take the square root of 4 to get your radius of 2
Then plot the center and create the circle
pic shown below:
