How does the graph of y = sec(x + 3) – 7 compare with the graph of y = sec(x)?

Mathematics

2 answers:

jarptica [38.1K]3 years ago

5 0

Answer:

Step-by-step explanation:

Alla [95]3 years ago

3 0

Answer:

The function y = sec(x) shifted 3 units left and 7 units down .

Step-by-step explanation:

Given the function: y = sec(x)

If k is any positive real number, then the graph of f(x) - k is the graph of y = f(x) shifted downward k units.

If p is a positive real number, then the graph of f(x+p) is the graph of y=f(x) shifted to the left p units.

The function $y = \sec(x+3)-7$ comes from the base function y= sec(x).

Since 3 is added added on the inside, this is a horizontal shift Left 3 unit, and since 7 is subtracted on the outside, this is a vertical shift down 7 units.

Therefore, the transformation on the given function is shifted 3 units left and 7 units down

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3 years ago

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pychu [463]

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the first thing we need to do is find 2 numbers that add up to equal the middle term (1) but multiply together to get a product of -72 (-12*6)

two numbers that would fit this is 9 and -8
so now we placed 9x and -8x in place of the middle term

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now we look for whats common between the first two numbers and divide them out

6x²+9x = 3x(2x+3)

now we do the same with the last two numbers

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notice how the numbers in brackets are the same (2x+3)
we will keep (2x+3) and then combine the numbers on the outside

once we do that you should get an answer of

(3x-4)(2x+3)

hope this helped!

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3 years ago

Which function is equivalent to y= -cot(x)

jeka94

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