Question

How does the graph of y = sec(x + 3) – 7 compare with the graph of y = sec(x)?

Answer 1

Answer:

C

Step-by-step explanation:

Answer 2

Answer:

The function y = sec(x) shifted 3 units left and 7 units down .

Step-by-step explanation:

Given the function: y = sec(x)

• If k is any positive real number, then the graph of f(x) - k is  the graph of y = f(x) shifted downward k units.

• If p is a positive real  number, then the  graph of f(x+p) is  the graph of y=f(x)  shifted to the left  p units.

The function $y = \sec(x+3)-7$ comes from the base function y= sec(x).  

Since 3 is added added on the inside, this  is a horizontal shift Left 3 unit, and since 7 is subtracted on the outside, this is a vertical shift  down 7 units.

Therefore, the transformation on the given function is shifted  3 units left and 7 units down