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ss7ja [257]
3 years ago
15

Tony solves the linear equation 3(x - 3) + 2x + 9 = 2x + 2(x - 1) using the step shown below.

Mathematics
1 answer:
Natasha_Volkova [10]3 years ago
8 0

Answer:

D.)

Step-by-step explanation:

because when you have numbers inside the parentheses, you have to multiply both of those numbers by the number to the right of the parentheses, not just the X.

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barxatty [35]

Answer:

Step-by-step explanation:

ABC and DEF are parallel lines. So, ∠ABE and ∠BED are co interior angles.

∠ABE + ∠BED = 180   {SUM OF CO INTERIOR ANGLE IS 180}

∠ABE+ 110.2 = 180

∠ABE = 180 - 110.2

∠ABE = 69.8

Now, ABC is straight line

∠ABE + ∠EBG + ∠CBG = 180

69.8 + ∠EBG + 34.8 = 180

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∠EBG = 180 - 104.6

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∠DEB + ∠BEG + ∠GEF = 180

110.2 + ∠BEG + 25.6 = 180

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∠BEG = 180 - 135.8

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In triangle BEG,

∠BEG + x  + ∠EBG = 180  { sum of all angles of triangle is 180}

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3 years ago
Simplity find the quotient and the remainder of (2x2+9x+8)÷(x+2)​
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Answer:

Step-by-step explanation:

\alpha+\beta=\dfrac{5}{2} \\\\\alpha*\beta=\dfrac{1}{2} \\\\\alpha^2+\beta^2=\dfrac{21}{4} \ (see\ previous\ post)\\\\(\alpha+\beta)^4=\dfrac{625}{16} \\\\=\alpha^4+\beta^4+4*\alpha^3*\beta+6*\alpha^2*\beta^2+4*\alpha*\beta^3\\\\=\alpha^4+\beta^4+4*(\alpha*\beta)(\alpha^2+\beta^2)+6*\alpha^2*\beta^2\\\\\alpha^4+\beta^4=(\alpha+\beta)^4-4*(\alpha*\beta)(\alpha^2+\beta^2)-6*\alpha^2*\beta^2\\\\= \dfrac{625}{16} -4*\dfrac{1}{2} *\dfrac{21}{4} -6*(\dfrac{1}{2})^2 \\\\

= \dfrac{625}{16}- \dfrac{168}{16}-\dfrac{24}{16}\\\\\\= \dfrac{433}{16}

7 0
3 years ago
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