Answer:
There is 3 sulfur and 12 oxygen atoms
The oxidation half equation is Zn ------> Zn^2+ + 2e while the reduction half equation is Cu^2+ + 2e------> Cu.
A redox reaction is a reaction in which there is a loss/gain of electrons. The specie that gives out electrons experiences an increase in oxidation number while the specie that gains the electrons experiences a decrease in oxidation number.
For the reaction; CuCl2 + Zn → ZnCl2 + Cu
The oxidation half equation is;
Zn ------> Zn^2+ + 2e
The reduction half equation is;
Cu^2+ + 2e------> Cu
The chloride ion is excluded because its oxidation number does not change from left to right in the reaction.
Learn more: brainly.com/question/967776
Answer:
9.86*10^(-3) g
Explanation:
PbSO4 ----> Pb^(2+) + SO4^(2-)
s s
Ksp = s²
s =√Ksp = √(1.8*10^-8) = 1.3*10^(-4) mol/L
The molar solubility PbSO4 = 1.3*10^(-4) mol/L.
2.50 *10^2 mL *1L/10³mL =0.250L
1.3*10^(-4)mol/L *0.250L*303.3 g/mol = 9.86*10^(-3) g
Answer: 4 mol
C + 2S = CS2
1 mol of CS2 contains 2 mol of sulfur
So 2 mol of cs2 contains 2*2 mol of S
2mol CS2 x 2 mol S/ 1 mol CS2 =
4 mol S
Answer : The mass of sucrose added to 375 mL of water must be, 10.6 grams.
Explanation :
As we are given that 2.75 m/m percent solution of sucrose. That means, 2.75 grams of sucrose present in 100 grams of solution.
Mass of solution = 100 g
Mass of sucrose = 2.75 g
Mass of water = Mass of solution - Mass of sucrose
Mass of water = 100 g - 2.75 g
Mass of water = 97.25 g
First we have to calculate the mass of water.
Density of water = 1.00 g/mL
Volume of water = 375 mL
Now we have to calculate the mass of sucrose in 375 g of water.
As, 97.25 grams of water contain 2.75 grams of sucrose
So, 375 grams of water contain 
grams of sucrose
Therefore, the mass of sucrose added to 375 mL of water must be, 10.6 grams.
