Answer:
Light
Explanation:
Plant is a thing so it has matter
Cheese is food so it has matter
Blood is a liquid so it has matter
Thermohaline circulation that occur in the ocean part that flows across sea surface help to supply heat to polar regions.
<h3>What is Thermohaline circulation?</h3>
The thermohaline circulation refer to a section and region of the ocean circulation which is majorly driven by heat gradient and freshwater that flows across the sea surface and also from the mixture of heat and salt that occur at the inside part of the ocean.
Therefore, Thermohaline circulation help to supply heat to polar regions.
Learn more about thermohaline circulation here.
brainly.com/question/1176119
Answer:
- <em>The solution expected to contain the greatest number of solute particles is: </em><u>A) 1 L of 1.0 M NaCl</u>
Explanation:
The number of particles is calculated as:
a) <u>For Ionic compounds</u>:
- molarity × volume in liters × number of ions per unit formula.
b) <u>For covalent compounds</u>:
- molarity × volume in liters
The difference is a factor which is the number of particles resulting from the dissociation or ionization of one mole of the ionic compound.
So, calling M the molarity, you can write:
- # of particles = M × liters × factor
This table show the calculations for the four solutions from the list of choices:
Compound kind Particles in solution Molarity # of particles
(dissociation) (M) in 1 liter
A) NaCl ionic ions Na⁺ and Cl⁻ 1.0 1.0 × 1 × 2 = 2
B) NaCl ionic ions Na⁺ anc Cl⁻ 0.5 0.5 × 1 × 2 = 1
C) Glucose covalent molecules 0.5 0.5 × 1 × 1 = 0.5
D) Glucose covalent molecules 1.0 1.0 × 1 × 1 = 1
Therefore, the rank in increasing number of particles is for the list of solutions given is: C < B = D < A, which means that the solution expected to contain the greatest number of solute particles is the solution A) 1 L of 1.0 M NaCl.
Answer;
=28.09 amu
Explanation;
In this problem, they did not give us the percentages. However, since we know the number of atoms, we can easily calculate the percentages. For example:
(460 X 100)/500 = 92%
If we do this for all three isotopes,
(460 × 25)/500 = 5 %
(460 × 15) /500 = 3%
-We get 92%, 5%, and 3%. (We'll assume these are absolute numbers for determining our significant figures).
Now the problem is just like the previous one. First convert the percentages into decimals. Then multiply those decimals by the masses and add. Here's the solution:
= (0.92) X (27.98 amu) + (0.05) X (28.98 amu) + (0.03) X (29.97 amu)
= 25.74 amu + 1.449 amu + 0.8991 amu
= 28.09 amu
