Question

How many moles of potassium chloride and oxygen can be produced from 100.0g of potassium chlorate? The balanced equation is: 2 KClO3=2KCL+3O2

Answer 1

Answer : The moles of potassium chloride and oxygen produced can be 0.813 and 2.44 respectively.

Explanation : Given,

Mass of $KClO_3$ = 100.0 g

Molar mass of $KClO_3$ = 123 g/mole

The balanced chemical reaction will be,

$2KClO_3\rightarrow 2KCl+3O_2$

First we have to calculate the moles of $KClO_3$.

$\text{ Moles of }KClO_3=\frac{\text{ Mass of }KClO_3}{\text{ Molar mass of }KClO_3}=\frac{100.0g}{123g/mole}=0.813moles$

Now we have to calculate the moles of $KCl$ and $O_2$.

From the balanced chemical reaction we conclude that,

As, 2 mole of $KClO_3$ react to give 2 mole of $KCl$

So, 0.813 mole of $KClO_3$ react to give 0.813 mole of $KCl$

and,

As, 2 mole of $KClO_3$ react to give 3 mole of $O_2$

So, 0.813 mole of $KClO_3$ react to give 3 × 0.813 = 2.44 mole of $O_2$

Therefore, the moles of potassium chloride and oxygen produced can be 0.813 and 2.44 respectively.

Answer 2

100.0 g KClO₃ × 1 mol KClO₃/122.55 g KClO₃ × 2 mols KCl/2 mols KClO₃= 0.8160 mols of KCl

100.0 g KClO₃ × 1 mol KClO₃/122.55 g KClO₃ × 3 mols O₂/ 2 mols KClO₃= 1.224 mols of O₂

try this

122.55 g is molar mass of potassium chlorate