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joja [24]
3 years ago
6

A cook had a jar containing a sweet food and a jar containing a sour food. The image above shows the sweet and sour foods. At ro

om temperature, both foods are liquids. The same amount of energy was transferred into both substances. Later, one of the foods had changed phase while the other had not. Which food changed phase, and how did it change? PLEASE ANSWER ASAP
Chemistry
1 answer:
mamaluj [8]3 years ago
5 0

Answer: One of the foods was sour and one was sweet

Explanation:

The sweet one has changed because it has more sugar then the sour one, It either got moldy or melted.

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75.0 grams of MgCl, is dissolved in 500.0 g of water, density 1.00 g/ml. What is the MOLALITY of this solution?
ollegr [7]

Answer:

C

Explanation:

Check it. So u can know it

8 0
2 years ago
A scientist has two samples of gas: The first sample contains one mole of argon atoms and has a mass of 39.948 g; the second sam
V125BC [204]

There are 6.022 × 10²³ atoms in 39.948 g of argon and 4.0026 g of helium.

Explanation:

39.945 g/mole is the molar mass of argon so 39.948 g of argon are equal to 1 mole of argon.

4.0026 g/mole is the molar mass of helium so 4.0026 g of helium are equal to 1 mole of helium.

We know that Avogadro's number tell us the number of particles in 1 mole of substance which is 6.022 × 10²³.

So in 39.948 g of argon and 4.0026 g of helium contains the same number of atoms, 6.022 × 10²³.

Learn more about:

Avogadro's number

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4 0
3 years ago
These substances are all ____. H2O2 Li NaCl O2
Bogdan [553]

Answer: pure substances.


Explanation:


The given substances are:

  • H₂O₂
  • Li
  • NaCl
  • O₂

All what surrounds us, which has mass and occupies spaces, is matter. There are two kind of matter: pure substances and mixtures.


Pure substances have a uniform and constant composition. On the other hand, mixtures are combinations of two or more pure substances in  any arbitratry ratio.


Pure substances may be elements or compounds. The elements are the substances conmposed by one only kind of atom. In the list of substances given, Li and O₂ are elements: all the atoms in Li are lithium, and all the atoms in O₂ are oxygen atoms.


Compounds are the chemical combination of two or more different kind of atoms. In the given list H₂O₂ and NaCl are compounds. As you see, H₂O₂ contains atoms of hydrogen and oxygen, chemically bonded, in a fixed ratio (2 atoms of hydrogen by 2 atoms of oxygen). And NaCl has atoms of Na (sodium) and Cl (chlorine), chemicaly bonded, in a fixed ratio (1:1).


There are only 118 known elements and you can find them in any modern periodic table. Therer are virtually infinitely many compounds since many different combinations of the elements can be attained.


Elements and compounds have in common that they are classified as pure substances.


7 0
3 years ago
If 40.0 mL of a calcium nitrate solution reacts with excess potassium carbonate to yield 0.524 grams of a precipitate, what is t
tankabanditka [31]

Answer : The molarity of calcium ion on the original solution is, 0.131 M

Explanation :

The balanced chemical reaction is:

Ca(NO_3)_2+K_2CO_3\rightarrow CaCO_3+3KNO_3

When calcium nitrate react with potassium carbonate to give calcium carbonate as a precipitate and potassium nitrate.

First we have to calculate the moles of CaCO_3

\text{Moles of }CaCO_3=\frac{\text{Mass of }CaCO_3}{\text{Molar mass of }CaCO_3}

Given:

Mass of CaCO_3 = 0.524 g

Molar mass of CaCO_3 = 100 g/mol

\text{Moles of }CaCO_3=\frac{0.524}{100g/mol}=0.00524mol

Now we have to calculate the concentration of CaCO_3

\text{Concentration of }CaCO_3=\frac{\text{Moles of }CaCO_3}{\text{Volume of solution}}=\frac{0.00524mol}{0.040L}=0.131M

Now we have to calculate the concentration of calcium ion.

As, calcium carbonate dissociate to give calcium ion and carbonate ion.

CaCO_3\rightarrow Ca^{2+}+CO_3^{2-}

So,

Concentration of calcium ion = Concentration of CaCO_3 = 0.131 M

Thus, the concentration or molarity of calcium ion on the original solution is, 0.131 M

4 0
3 years ago
Why is it better to use deionized water in chemistry experiments
Leno4ka [110]

Answer:

Laboratories use both distilled water and deionized water as controls in experiments. Deionization removes only non-charged organic matter from the water.

Explanation:

Distilled water removes even more impurities than deionization does, if the water undergoes a filtering process before boiling and distillation.

6 0
3 years ago
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