How do u simplify these radicals???

Mathematics

1 answer:

AlladinOne [14]3 years ago

4 0

1. √48 → √16 * √3  =  4√3

3. √12 → √4 * √3 = 2√3

7. √125  → √25 * √5 = 5√5

8. √20  →  √4 *  √5 = 2√5

9.  √18  →  √9 *  √2 = 3√2

10. √32  →  √16 *  √2 = 4√2

11.  √50  →  √25 *  √2 = 5√2

12.  √27  →  √9 * √3 = 3√3

You might be interested in

|n/2 − 1/3| −1= 1/6

weqwewe [10]

1. n/2-1/3-1=1/6
n/2=1/6+1/3+1
n/2=1/6+2/6+6/6
n/2=9/6=3/2
n=3/2*2=3

check: abs(3/2-1/3)-1=1/6, abs(9/6-2/6)-1= 1/6, 7/6-1=1/6, 1/6 =1/6
3 is a root

2. -(n/2-1/3)-1=1/6
-n/2+1/3-1=1/6
-n/2-2/3=1/6
-n/2=1/6+2/3
-n/2=1/6+4/6
-n/2=5/6
n=-2*5/6=-5/3=-1 2/3
check : abs((-5/3)/2-1/3) -1=1/6
abs(-5/6-1/3) -1 =1/6, abs(-5/6-2/6) -1=1/6, abs (-7/6)-1=1/6, 7/6-1=1/6, 1/6=1/6
so -5/3 or -1 2/3 is also root

so two roots 3 and -5/3(that can be written as -1 2/3)

5 0

3 years ago

a student measured the temperature in degrees celsius for several winter days and recorded the data in a list find the average o

NemiM [27]

Answer:

Average = -1°C

Step-by-step explanation:

The data recorded is;

6, -7, -5, 5, -8, 3 (in °C)

Average = $\frac{6 - 7 - 5 + 5 - 8 + 3}{6}$ = -1°C