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Gnesinka [82]
3 years ago
11

Freight cars on some trains can each haul 60 tons of cargo. How many 500​-pound containers can be hauled by this type of freight

​ car, assuming that all containers fit on the​ car?
Mathematics
1 answer:
zavuch27 [327]3 years ago
5 0

Answer:240 500 pounds containers

Step-by-step explanation:

Each ton is 2000 pounds.? Convert 60 tons to pounds to get 120000 pounds and then divide it by 500

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(m^-4/3)^1/4 divided by m^0 n^3/4(m^-3/2 n^2)
postnew [5]
\frac{(m^{-\frac{4}{3}})^{\frac{1}{4}}}{m^{0}(m^{-\frac{3}{2}}n^{2})} = \frac{m^{-\frac{1}{3}}}{m^{-\frac{3}{2}}n^{2}} = \frac{m^{\frac{3}{2}}}{m^{\frac{1}{3}}n^{2}} = \frac{m^{\frac{7}{6}}}{n^{2}} = \frac{\sqrt[6]{m^{7}}}{n^{2}} = \frac{\sqrt[6]{m^{6} * m}}{n^{2}} = \frac{\sqrt[6]{m^{6}}\sqrt[6]{m}}{n^{2}} = \frac{m\sqrt[6]{m}}{n^{2}}
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3 years ago
Lexi Susie and Ryan are playing on online word game Royals score 100034 points Lexi scores 9348 fewer points t
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7 0
4 years ago
The given line passes through the points and (-4, -3) and (4, 1).
Debora [2.8K]

Answer:

The equation of the line is y - 3 = -2(x + 4)

Step-by-step explanation:

* Lets explain how to solve the problem

- The slope of the line which passes through the points (x1 , y1) and

  (x2 , y2) is m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}

- The product of the slopes of the perpendicular lines = -1

- That means if the slope of a line is m then the slope of the

  perpendicular line to this line is -1/m

- The point-slope of the equation is y - y_{1}=m(x - x_{1})

* lets solve the problem

∵ A given line passes through points (-4 , -3) and (4 , 1)

∴ x1 = -4 , x2 = 4 and y1 = -3 , y2 = 1

∴ The slope of the line m=\frac{1-(-3)}{4-(-4)}=\frac{1+3}{4+4}=\frac{4}{8}=\frac{1}{2}

- The slope of the line perpendicular to this line is -1/m

∵ m = 1/2

∴ The slope of the perpendicular line is -2

- Lets find the equation of the line whose slope is -2 and passes

 through point (-4 , 3)

∵ x1 = -4 , y1 = 3

∵ m = -2

∵ y - y1 = m(x - x1)

∴ y - 3 = -2(x - (-4))

∴ y - 3 = -2(x + 4)

* The equation of the line is y - 3 = -2(x + 4)

4 0
3 years ago
At a high school, students can choose between three art electives, four history electives, and five computer electives. Each stu
V125BC [204]

Answer:

\frac{^3C_1\times ^4C_1}{^{12}C_2}

Step-by-step explanation:

Given,

Art electives = 3,

History electives = 4,

Computer electives = 5,

Total number of electives = 3 + 4 + 5 = 12,

Since, if a student chooses an art elective and a history elective,

So, the total combination of choosing an art elective and a history elective = ^3C_1\times ^4C_1

Also, the total combination of choosing any 2 subjects out of 12 subjects = ^{12}C_2

Hence, the probability that a student chooses an art elective and a history elective = \frac{\text{Total combination of choosing an art elective and a history}}{\text{ Total combination of choosing any 2 subjects}}

=\frac{^3C_1\times ^4C_1}{^{12}C_2}

Which is the required expression.

3 0
3 years ago
Read 2 more answers
Which triangles are congruent by SAS?
boyakko [2]

Answer:

Option A

Triangles ABC and TUV

Step-by-step explanation:

Given three triangles ABC , FGH and TUV

For triangles ABC and FGH, given that

DF =AB

DH = AC

and angle F = angle A

This cannot be taken as SAS congruence because the angle F is not included between the equal sides.  Two triangles can be congruent by SAS only if two sides and included angle are congruent.

For triangles ABC and TUV we have AB=TU, AC = TV and

included angles between these sides are equal.

So these two triangles are congruent

We write corresponding sides only in order Hence ABC = TUV

and Not VTU =ABC

So option A is true.

5 0
3 years ago
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