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Tcecarenko [31]
3 years ago
13

54d. Change the following expression into a single fraction: 5b − 2/b

Mathematics
1 answer:
lisabon 2012 [21]3 years ago
6 0
9/2b is the answer..
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Which expression is equivalent to (x Superscript 27 Baseline y) Superscript one-third?
Kay [80]

Answer:

um i cannot understand that ok ?

Step-by-step explanation:

6 0
3 years ago
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(6x10^2)/(3x10-5) help what is this in standard form?
Tasya [4]

<u>Answer: </u>

The standard form of \frac{6 \times 10^{2}}{3 \times 10^{-5}} is 20,00,0000

<u>Solution: </u>

Given that \frac{6 \times 10^{2}}{3 \times 10^{-5}} ---- eqn 1

To write\frac{6 \times 10^{2}}{3 \times 10^{-5}} in standard form,

We know that \bold{\frac{1}{a^{-m}} = a^{m}} .So \frac{1}{10^{-5}}  becomes 10^{5}.

Now eqn 1 becomes,

= \frac{6 \times 10^{2}}{3} \times 10^{5} ----- eqn 2

We know that \bold{a^{m} \times a^{n}=a^{m+n}}, so 10^{2} \times 10^{5} = 10^{7}

Now eqn 2 becomes,

= \frac{6}{3} \times 10^{7}

= 2 \times 10^{7} ---- eqn 3

Expanding 10^{7}:  

Here 10 is the base term and 7 is the exponent value. So base term 10 is multiplied by itself 7 times.

10^{7} = 10 \times 10 \times 10 \times 10 \times 10 \times 10 \times 10

Now eqn 3 becomes,

= 2 \times 10 \times 10 \times 10 \times 10 \times 10 \times 10 \times 10

= 20,00,0000  

Hence the standard form of \frac{6 \times 10^{2}}{3 \times 10^{-5}} is 20,00,0000

6 0
3 years ago
Answer the following questions CORRECTLY I will know if this is wrong. I WILL REPORT ANY INCORRECT ANSWERS!
LenKa [72]

Answer by JKismyhusbandbae: This explanation is short and sweet. An equation states that two things are equal. It will have an equals sign "="

7 0
3 years ago
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2. 6(6n + 2) + 9(-8n - 1)
spayn [35]

Answer:

2. the final answer is -36n+3

3. the final answer is -4x-10

4. the final answer is 3c-81

5. the final answer is 17b-31

6. the final answer is 56y+64

7. the final answer is 24q+30

Note: I simplify each problem

5 0
3 years ago
Val needs to find the area enclosed by the figure. The figure is made by attaching semicircles to each side of a 58 dash m​-by-5
svetoff [14.1K]

Answer:

We need to find the area of the semicircles + the area of the square.

The area of a square is equal to the square of the lenght of one side.

As = L^2 = 58m^2 = 3,364 m^2

Now, each of the semicircles has a diameter of 58m, and we have that the area of a circle is equal to:

Ac = pi*(d/2)^2 = 3.14*(58m/2)^2 = 3.14(27m)^2 = 2,289.06m^2

And the area of a semicircle is half of that, so the area of each semicircle is:

a =  (2,289.06m^2)/2 = 1,144.53m^2

And we have 4 of those, so the total area of the semicircles is:

4*a = 4* 1,144.53m^2 = 4578.12m^2

Now, we need to add the area of the square 3,364 m^2 + 4578.12m^2 = 7942.12m^2

This is nothing like the provided anwer of Val, so the numbers of val may be wrong.

5 0
3 years ago
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