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klasskru [66]
3 years ago
11

If p varies inversely with q, and p = 2 when q = 1, find theequation that relates p and q.​

Mathematics
1 answer:
NeTakaya3 years ago
3 0

Answer:

p = \frac{2}{q}

Step-by-step explanation:

Given that p varies inversely with q then the equation relating them is

p = \frac{k}{q} ← k is the constant of variation

To find k use the condition p = 2 when q = 1, thus

k = pq = 2 × 1 = 2

p = \frac{2}{q} ← equation of variation

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If he will be making each tablecloth of equal size, then they will be 3 1/3 yards each, also could be shown as 10 feet, because 10 ÷ 3 = 3 1/3.
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If Sarah is planning a trip to an amusement park, and 410 people are going, how many buses are needed to transport everyone if 4
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Let x²y +ay² = b be an Implicitly defined function, where a and b are fixed Constants; find dy/dx
geniusboy [140]

The value of the differential with respect to x is -xy/x²+ay

<h3>Implicit differentiation</h3>

Given the following function

x²y +ay² = b

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Put the following equation of a line into slope-intercept form, simplifying all fractions.
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3 years ago
Evelyn wants to estimate the percentage of people who own a tablet computer she surveys 150 indvidals and finds that 120 own a t
igomit [66]

Answer:

The 99% confidence interval for the percentage of people who own a tablet computer is between 71.59% and 88.41%

Step-by-step explanation:

Confidence interval for the proportion of people who own a tablet:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

For this problem, we have that:

n = 150, \pi = \frac{120}{150} = 0.8

99% confidence level

So \alpha = 0.01, z is the value of Z that has a pvalue of 1 - \frac{0.01}{2} = 0.995, so Z = 2.576.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.8 - 2.575\sqrt{\frac{0.8*0.2}{150}} = 0.7159

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.8 + 2.575\sqrt{\frac{0.8*0.2}{150}} = 0.8841

Percentage:

Multiply the proportion by 100.

0.7159*100 = 71.59%

0.8841*100 = 88.41%

The 99% confidence interval for the percentage of people who own a tablet computer is between 71.59% and 88.41%

8 0
3 years ago
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