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Brrunno [24]
3 years ago
10

An Earth satellite moves in a circular orbit 680 km above Earth's surface with a period of 98.15 min. What are (a) the speed and

(b) the magnitude of the centripetal acceleration of the satellite

Physics
1 answer:
kotykmax [81]3 years ago
6 0

The solution is in the attachment

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Which of the following must an engineer take into account when designing a roller coaster?
saveliy_v [14]

Answer:

The correct answer would be A

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Elevator mass 750kg tension on cable 8950n what is the net force action on the elevator
Hunter-Best [27]
The answer to this question i think would be 8950. Do you have any answer choices.
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4 years ago
Suppose a force of 30 N is required to stretch and hold a spring 0.2 m from its equilibrium position.
nydimaria [60]

Answer:

a. k=150N/m, b.W=0.75J,c. W=12J, d.W=9J

Explanation:

a. The Hooke's Law statesF=kx, where F is the force, k the spring constant and x the displacement, Knowing the force and the displacement you can find k:

F=kx

k=\frac{F}x=\frac{30}{0.2}=150N/m

b. The work done by a force F(s) that moves along a displacement s is:

W=\int\limits^{x_2}_{x_1} {F(s)} \, ds

ThenF(s)=ks (Hooke's Law)

W=\int\limits^{x_2}_{x_1} {F(s)} \, ds=\int\limits^{x_2}_{x_1} {ks} \, ds=\frac{1}{2} ks^2|\limits^{x_2}_{x_1}=\frac{1}{2} k(x_2^2-x_1^2)

Work needed to go from  x_1=0 to x_2=0.1

W=\frac{1}{2} k(x_2^2-x_1^2)=\frac{1}{2} 150(0.1^2-0^2)=75(0.01)=0.75 J

c. Work needed to go from x_1=0 to x_2=0.4

W=\frac{1}{2} k(x_2^2-x_1^2)=\frac{1}{2} 150(0.4^2-0^2)=75(0.16)=12 J

d. Work needed to go from x_1=0.2 to x_2=0.4

W=\frac{1}{2} k(x_2^2-x_1^2)=\frac{1}{2} 150(0.4^2-0.2^2)=75(0.16-0.04)=75(0.12)=9 J

5 0
3 years ago
The standard normal curve is not symmetrical. <br> a. True<br> b. False
FrozenT [24]

Answer;

The above statement is false

Explanation;

Symmetrical distribution, commonly known as symmetric distribution or normal distribution, is typically unimodal, meaning it shows only one peak in graph form.

It is a type of distribution where the left side of the distribution mirrors the right side. By definition, a symmetric distribution is never a skewed distribution.

All normal distributions are symmetric and have bell-shaped density curves with a single peak.

7 0
3 years ago
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How can we reduce friction
uysha [10]

Answer:

Smoother surfaces, and less contact between objects.

Explanation:

Smoother surfaces create less friction and drag among the object pulled, so we definitely need those kinds of surfaces to reduce friction.

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