Consider a series of motion scenarios. Each scenario is accompanied by a short description and an arrow indicating the instantan
eous velocity. Assume that air resistance is negligible in every scenario. The only forces present in each scenario are gravity, surface (or normal) forces, and friction if indicated. Place the appropriate arrow, or zero, next to each scenario to indicate the direction of the net force acting on the block.
1 answer:
You might be interested in
Answer:
Team A has the greatest momentum
Explanation:
The momentum of an object is a vector quantity given by
where
m is the mass of the object
v is its velocity
In this problem, we have to compare the momenta of the different sleds.
We have:
A) Sled Team A 48 kg moving at 10m/s:
m = 48 kg
v = 10 m/s
p = (48)(10) = 480 kg m/s
B) Sled Team B 14 kg moving at 18m/s
m = 14 kg
v = 18 m/s
p = (14)(18) = 252 kg m/s
C) Sled Team C 28 kg moving at 12m/s
m = 28 kg
v = 12 m/s
p = (28)(12) = 336 kg m/s
D) Sled Team D 22 kg moving at 12m/s
m = 22 kg
v = 12 m/s
p = (22)(12) = 264 kg m/s
So, team A has the greatest momentum.
Answer:
The rate of change of distance between the two ships is 18.63 km/h
Explanation:
Given;
distance between the two ships, d = 140 km
speed of ship A = 30 km/h
speed of ship B = 25 km/h
between noon (12 pm) to 4 pm = 4 hours
The displacement of ship A at 4pm = 140 km - (30 km/h x 4h) =
140 km - 120 km = 20 km
(the subtraction is because A is moving away from the initial position and the distance between the two ships is decreasing)
The displacement of ship B at 4pm = 25 km/h x 4h = 100 km
Using Pythagoras theorem, the resultant displacement of the two ships at 4pm is calculated as;
r² = a² + b²
r² = 20² + 100²
r = √10,400
r = 101.98 km
The rate of change of this distance is calculated as;
r² = a² + b²
r = 101.98 km, a = 20 km, b = 100 km