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xxMikexx [17]
3 years ago
13

An electromagnetic wave traveling in a

Physics
1 answer:
siniylev [52]3 years ago
3 0
Answer would be c as shown in the photo

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Can someone help me?!!!!!
Bingel [31]

Answer:

Third Option

B = -0.5A

Explanation:

If we have a vector A = ax + by we know that by definition

cA = cax + cby

Where c is a constant.

In this case we have two vectors

A = 7.6\^x -9.2\^y\\\\B = -3.8\^x + 4.6\^y

You may notice that vector B has an opposite direction to vector A.

You may also notice that | Ax | is the double of | Bx | and | Ay | is double of |By |

That is to say

3.8 +3.8 = 7.6\\\\4.6 +4.6 = 9.2

So the equation that relates to vectors A and B is:

B = -0.5A.

You can verify this relationship by performing the operation

B = -0.5A

-3.8\^x + 4.6\^y = -0.5(7.6\^x -9.2\^y)\\\\\-3.8\^x + 4.6\^y = -3.8\^x + 4.6\^y

4 0
4 years ago
Read 2 more answers
❍The period of oscillation of the single pendulum depends on its length and acceleration for the period of oscillation. Derive t
kirill115 [55]

  • <em>each complete oscillation, called the period, is constant. The formula for the period T of a pendulum is T = 2π Square root of√L/g, where L is the length of the pendulum and g is the acceleration due to gravity.</em>

<h2><em>hope</em><em> it</em><em> helps</em><em>!</em></h2>

5 0
3 years ago
Which statement would most likely be found in an advertisement from a <br> cell phone provider
ki77a [65]

Answer:B

Explanation:

3 0
4 years ago
Q6. When a girl steps on to a weighing machine, it shows a reading of 42kg.
tigry1 [53]

Answer:

92.5 pounds

Explanation:

5 0
2 years ago
What is the magnification of a virtual image if the image is 60.0 cm from a
Hatshy [7]

Answer:

4cm

Explanation:

Magnification of the virtual image

= image distance / object distance

Given

Image distance = 60.0cm

Object distance = 15.0cm

Therefore,

Magnification = 60.0/15.0

= 4 cm

6 0
3 years ago
Read 2 more answers
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