Answer:
3.06m/s² to the east
Explanation:
Given parameters:
Mass of car = 2.5 x 10³kg
Force acting on the car = 7.65 x 10³N
Unknown:
Acceleration of the car = ?
Solution:
From Newton's second law of motion:
Force = mass x acceleration
Acceleration = 
= 
= 3.06m/s² to the east
Since the circuit is incomplete or not closed, no current flows in the circuit. as per ohm's law , Voltage is directly proportional to current and is given as
V = Voltage = i R where i = current , R = resistance
as no current flows in the circuit, i = 0
the resistance R can not be zero. hence
V = 0 (R)
V = 0 Volts
so the magnitude of the Voltage is zero Volts
Answer:
33 N
Explanation:
v = Velocity of fluid = 8+2 = 10 m/s
= Density of fluid = 1.2 kg/m³
C = Coefficient of drag = 1.1
A = Cross sectional area = 0.5 m²
Drag force is given by
The drag force on the athlete is 33 N
☁️ Answer ☁️
annyeonghaseyo!
Your answer is:
True.
Several simple machines change the direction of the applied force. These include lever, fulcrum and the pulley.
Hope it helps.
Have a nice day hyung/noona!~ ￣▽￣❤️
Answer:
–50.96
Explanation:
The following data were obtained from the question:
Initial velocity (Vᵢ) = 0 m/s
Acceleration (a) = – 9.8 m/s²
Time (t) = 5.2 s
Final velocity (Vբ) =.?
Acceleration is simply defined as the change of velocity with time. Mathematically, it is expressed as:
Acceleration (a) = Final velocity (Vբ) – Initial velocity (Vᵢ) /Time (t) =
a = (Vբ – Vᵢ) / t
With the above formula, we can determine how fast the object is traveling after 5 s as follow:
Initial velocity (Vᵢ) = 0 m/s
Acceleration (a) = – 9.8 m/s²
Time (t) = 5.2 s
Final velocity (Vբ) =.?
a = (Vբ – Vᵢ) / t
– 9.8 = (Vբ – 0) / 5.2
– 9.8 = Vբ / 5.2
Cross multiply
Vբ = –9.8 × 5.2
Vբ = –50.96 m/s
Therefore, the object is traveling at
–50.96 m/s
