Can someone please answer 5, 6 and 7? Thank you.

Eight minus two times a number is equal to the number plus 17. Find the number.

navik [9.2K]

the answer is 8-2n=n+17 n=-3

3 0

3 years ago

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Y + 1 1/6 = 7 5/6 what is Y

AfilCa [17]

Answer:

6 $\frac{2}{3}$

Step-by-step explanation:

y + 1 $\frac{1}{6}$ = 7 $\frac{5}{6}$

y + $\frac{7}{6}$ = $\frac{47}{6}$

y = 40/6 = 20/3 = 6 $\frac{2}{3}$

3 0

3 years ago

A carpect salesperson claims that a carpet on sid for $12.95 per square yard is 30% off its original price. What was its origina

Amiraneli [1.4K]

12.95 30
-------- = ----
x 100

1295 = 30x
------- -----
30 30

x = 43.16666667

not sure how u want to round

8 0

2 years ago

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What is the slope of a line parallel to the line whose equation is 3x – 4y = 8

liq [111]

Hi there! The answer is C.

We can find the slope of this line by making y the subject of the equation.

$3x - 4y = 8 \\ - 4y = - 3x + 8 \\ y = \frac{ - 3}{ - 4} x + \frac{8}{ - 4} \\ y = \frac{3}{4} x - 2$

Now we can see that the slope of this line (which is positioned in front of x) is 3/4. Therefore, the slope of any line parallel to this one is 3/4 as well. The answer is C.

7 0

2 years ago

a. Among a shipment of 5,000 tires, 1,000 are slightly blemished. If one purchases 10 of these tires, what is the probability th

hodyreva [135]

Answer:

<h2>See the explanation.</h2>

Step-by-step explanation:

3 or less than 3 tires among the 10 tires should be blemished.

There are some possibilities.

1000 tires are blemished, (5000 - 1000) = 4000 tires are not blemished.

From the 5000 tires, 10 tires can be chosen in $^{5000}C_{10}$ ways.

Possibility 1: <u>3 tires are blemished.</u>

Total 10 tires can be chosen with 3 blemished tires in $^{1000}C_3 \times {4000}C_7$ ways.

Possibility 2: <u>2 tires are blemished.</u>

Total 10 tires can be chosen with 2 blemished tires in $^{1000}C_2 \times ^{4000}C_8$ ways.

Possibility 3: <u>1 tires are blemished.</u>

Total 10 tires can be chosen with 1 blemished tires in $^{1000}C_1 \times^{4000}C_9$ ways.

Possibility 4: <u>No tires are blemished.</u>

Total 10 tires can be chosen with no blemished tires in $^{1000}C_0 \times^{4000}C_{10}$ ways.

Hence, the required probability is $\frac{^{1000}C_1 \times^{4000}C_9 + ^{1000}C_0 \times^{4000}C_{10} + ^{1000}C_2 \times^{4000}C_8 + ^{1000}C_3 \times^{4000}C_7}{^{5000}C_{10} }$ .

6 0

2 years ago