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m_a_m_a [10]
3 years ago
8

Some people say that more babies are born in september than in any other month. to test this claim, you take a simple random sam

ple of 150 students at your school and find that 21 of them were born in september. you are interested in whether the proportion born in september is higher than 1/12—what you would expect if september was no different from any other month.
Mathematics
1 answer:
4vir4ik [10]3 years ago
4 0
Answer: Yes, 21 is higher than what you would expect if September was like any other month.

There are 12 months in the years. If all months were equally likely, then they would each have 1/12 of the babies.

1/12 of 150 is 12.5. The expected number of babies per month would be 12.5.

However, in the sample, there were 21 babies in September.
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At Garcia's Bike Rentals, it costs $13 to rent a bike for 3 hours. How many dollars does it cost per hour of bike use?
Naily [24]

Answer:

$4.33

Step-by-step explanation:

3 hours -> $13

1 hour -> $13/3 = $4.33

5 0
3 years ago
In parallelogram ABCD, the measure of angle A=3x and the measure of angle B =x+10. What is the measure of angle D?
Alinara [238K]

Answer: 52.5

Step-by-step explanation: 2(3x+10)+2(x+10)=360 because all the sides of a rhombus equal 360 and alternate sides are equal

8x+20=360

-20=-20

8x/8=340/8

x=42.5

x+10. 42.5+10=52.5

D=52.5

4 0
3 years ago
Please hurry
Studentka2010 [4]

Answer:

D 45.6 Square centimetres

Step-by-step explanation:

8 cm time 5.7 cm

8 0
3 years ago
At the U.S open tennis championship a statistician keeps track of every serve that a player hits during the tournament. The mean
GarryVolchara [31]

Answer:

Step-by-step explanation:

Both 115 and 145 mph are above the mean.  Draw a normal curve and mark these speeds.  115 mph is 1 standard deviation above the mean; 130 would be 2 standard deviations above the mean; and 145 would be 3 s. d. above it.

We need to find the area under the standard normal curve between 115 and 145.  This is equivalent to the area under the standard normal curve between z = 1 and z = 3.

I used my TI-83 Plus calculator's DISTR function "normalcdf(" to calculate this area:  normalcdf(1, 3) = 0.1573.

The area between z = 1 and z = 3 is 0.1573.  In other words, the percentage of serves that were between 115 and 145 mph was 15.73%.

8 0
3 years ago
Martina got a prepaid debit card with $20 on it. For her first purchase with the card, she bought some bulk ribbon at a craft st
Daniel [21]

Phone card = $20  

You need to minus 17.92 from 20 = $2.08  

$2.08 / 0.13 = how many minutes  

= 16

4 0
3 years ago
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