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bonufazy [111]
3 years ago
10

At the U.S open tennis championship a statistician keeps track of every serve that a player hits during the tournament. The mean

serve speed was 100 miles per hour and the standard deviation of the serve speeds was 15 mph. Assume the distribution of serve speeds was mound shaped and symmetric. What percentage of the playes serves were between 115 a nd 145 mph?
Mathematics
1 answer:
GarryVolchara [31]3 years ago
8 0

Answer:

Step-by-step explanation:

Both 115 and 145 mph are above the mean.  Draw a normal curve and mark these speeds.  115 mph is 1 standard deviation above the mean; 130 would be 2 standard deviations above the mean; and 145 would be 3 s. d. above it.

We need to find the area under the standard normal curve between 115 and 145.  This is equivalent to the area under the standard normal curve between z = 1 and z = 3.

I used my TI-83 Plus calculator's DISTR function "normalcdf(" to calculate this area:  normalcdf(1, 3) = 0.1573.

The area between z = 1 and z = 3 is 0.1573.  In other words, the percentage of serves that were between 115 and 145 mph was 15.73%.

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Answer:

23 tables.

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-5 1/2 + 6 3/4 + (-4 1/4)
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Answer:

-3

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-5 1/2 + 6 3/4 - 4 1/4

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What is 0.4 divided by 5.12 in long division
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Start by mult. both 0.4 and 5.12 by 100.  What is 40 divided by 512?

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512 /  40.000
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             4160
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A submarine sandwich 1.5feet long is cut into 0.25 foot pieces. how many pieces will there be?
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What is the equation of the line that is perpendicular to the given line and has an x-intercept of -3?
Anvisha [2.4K]

Answer:

y=-\frac{3}{2}x-\frac{9}{2}

Step-by-step explanation:

Let the equation of the perpendicular line is,

y = mx + b

where m = slope of the line

b = y-intercept

From the graph, slope of the line passing through (0, -1) and (3, 1),

m' = \frac{y_2-y_1}{x_2-x_1}

m' = \frac{1+1}{3-0}

m' = \frac{2}{3}

To get the slope (m) of this line we will use the property of perpendicular lines,

m × m' = (-1)

m × \frac{2}{3} = -1

m = -\frac{3}{2}

Equation of the perpendicular line will be,

y=-\frac{3}{2}x+b

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0 = -\frac{3}{2}(-3)+b

b = -\frac{9}{2}=-4.5

Equation of the line will be,

y=-\frac{3}{2}x-\frac{9}{2}

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3 years ago
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