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GenaCL600 [577]
3 years ago
13

Solve for x. -3x = -15 x = -5 x = 5 x = -45

Mathematics
2 answers:
Aleks [24]3 years ago
7 0

-3x = -15      <em>divide both sides by (-3)</em>

-3x:(-3)=-15:(-3)

x = 5

Gnom [1K]3 years ago
5 0

Answer:

The answer is b, 5

Step-by-step explanation:

-3x = -15

(it sometimes helps to flip it, so that's what I'm going to do here to help it to make more sense)

x(-3) = -15

x(-3) devided by (-3) = -15 devided by (-3)

when you devide a negitive by a negative the answer will be positive

the absolute value of 15 devided by three is 5

your answer is a positive five, or just 5


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The Brooklyn District Attorney's office analyzed the leading (leftmost) digits of check amounts in order to identify fraud. The
iragen [17]

Answer:

The expected number of checks among 784 that should have a leading digit of "1" is 236.

Step-by-step explanation:

Let <em>X</em> = number of checks that has the leading digit as "1".

The probability of a check having a leading digit as "1" is, <em>p</em> = 0.301.

The number of checks issued by a suspected company is, <em>n</em> = 784.

A check is having a leading digit "1" is independent of other checks.

A randomly selected check either has the leading digit 1 or not.

The success of the experiment is defined as, a check having the digit "1" as the leading digit.

The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> = 784 and <em>p</em> = 0.301.

The expected value of a random variable is the average number of times the random variable occurs.

The formula to compute the expected value of a Binomial distribution is:

E(X)=n\times p

Compute the expected value of <em>X</em> as follows:

E(X)=n\times p\\

         =784\times 0.301\\=235.984\\\approx236

Thus, the expected number of checks among 784 that should have a leading digit of "1" is 236.

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4 years ago
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Re-posting because I need help.. Please help and show how you got the answer..
Nesterboy [21]

Answer:

Explicit: -2*2^(n-1)

Recursive: 2*aₙ₋₁

Step-by-step explanation:

To write a explicit formula for this geometric sequence you follow the following formula/template

Firstnumber*commonratio^(n-1)

Seeing that the common ratio is 2 we can start plugging numbers in and get

-2*2^(n-1)

For a recursive formula we follow the following template

common ratio * the n-1 term

So we could write this as

2*aₙ₋₁

8 0
3 years ago
When dealing with the number of occurrences of an event over a specified interval of time or space, the appropriate probability
sdas [7]

Answer:

a)  Poisson distribution

use a  Poisson distribution model when events happen at a constant rate over time or space.

Step-by-step explanation:

<u> Poisson distribution</u>

  • Counts based on events in disjoint intervals of time or space produce a Poisson random variable.
  • A Poisson random variable has one parameter, its mean λ
  • The Poisson model uses a Poisson random variable to describe counts in data.

use a  Poisson distribution model when events happen at a constant rate over time or space.

<u>Hyper geometric probability distribution</u>:-

The Hyper geometric probability distribution is a discrete probability distribution that describes the probability of successes (random draws for which the object drawn has a specified feature) in draws without replacement, from a finite population of size that contains exactly objects with that feature where in each draw is either a success or failure.

This is more than geometric function so it is called the <u>Hyper geometric probability distribution </u>

<u></u>

<u>Binomial distribution</u>

  • The number of successes in 'n' Bernoulli trials produces a <u>Binomial distribution </u>. The parameters are size 'n' success 'p' and failure 'q'
  • The binomial model uses a binomial random variable to describe counts of success observed for a real phenomenon.

Finally use a Binomial distribution when you recognize distinct Bernoulli trials.

<u>Normal distribution</u>:-

  • <u>normal distribution is a continuous distribution in which the variate can take all values within a range.</u>
  • Examples of continuous distribution are the heights of persons ,the speed of a vehicle., and so on
  • Associate normal models with bell shaped distribution of data and the empirical rule.
  • connect <u>Normal distribution</u> to sums of like sized effects with central limit theorem
  • use histograms and normal quantile plots to judge whether the data match the assumptions of a normal model.

<u>Conclusion</u>:-

Given data use a  Poisson distribution model when events happen at a constant rate over time or space.

3 0
4 years ago
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