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3 years ago

I don't understand what the question is asking?

Mathematics

2 answers:

agasfer [191]3 years ago

7 0

Check the picture below.

bear in mind that 100/10 is 10, however, we have to include the very first post, which is not spaced away 10' from anywhere, is simply touching the barn wall. So the total is 10 spaced 10' from each other plus the starting post which is touching the barnwall. And you can start doing the counting from either side A or B and you'd get 11 total.

Notice the angle "tickmarks" btw, that means those two angles are equal, that means the triangle is an isosceles, and thus both of those sides are equal, so, if one is 50', the other is also 50'.

lana66690 [7]3 years ago

5 0

OK for this question you need to find out how many more post are needed. If you look at the diagram it shows that one side is 50 feet. Now there are two sides that will need post, because the barn side need no more. Now if there are two side both 50 feet, and you need a post every ten feet. How many posts are needed?

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Find the maximum and minimum values of the function f(x,y)=2x2+3y2−4x−5 on the domain x2+y2≤100. The maximum value of f(x,y) is:

ryzh [129]

First find the critical points of f :

$f(x,y)=2x^2+3y^2-4x-5=2(x-1)^2+3y^2-7$

$\dfrac{\partial f}{\partial x}=2(x-1)=0\implies x=1$

$\dfrac{\partial f}{\partial y}=6y=0\implies y=0$

so the point (1, 0) is the only critical point, at which we have

$f(1,0)=-7$

Next check for critical points along the boundary, which can be found by converting to polar coordinates:

$f(x,y)=f(10\cos t,10\sin t)=g(t)=295-40\cos t-100\cos^2t$

Find the critical points of g :

$\dfrac{\mathrm dg}{\mathrm dt}=40\sin t+200\sin t\cos t=40\sin t(1+5\cos t)=0$

$\implies\sin t=0\text{ OR }1+5\cos t=0$

$\implies t=n\pi\text{ OR }t=\cos^{-1}\left(-\dfrac15\right)+2n\pi\text{ OR }t=-\cos^{-1}\left(-\dfrac15\right)+2n\pi$

where n is any integer. We get 4 critical points in the interval [0, 2π) at

$t=0\implies f(10,0)=155$

$t=\cos^{-1}\left(-\dfrac15\right)\implies f(-2,4\sqrt6)=299$

$t=\pi\implies f(-10,0)=235$

$t=2\pi-\cos^{-1}\left(-\dfrac15\right)\implies f(-2,-4\sqrt6)=299$

So f has a minimum of -7 and a maximum of 299.

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2 years ago

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grigory [225]

Answer:

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then you take the square root of .16 and get .4

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