I don't understand what the question is asking?
2 answers:
Check the picture below.
bear in mind that 100/10 is 10, however, we have to include the very first post, which is not spaced away 10' from anywhere, is simply touching the barn wall. So the total is 10 spaced 10' from each other plus the starting post which is touching the barnwall. And you can start doing the counting from either side A or B and you'd get 11 total.
Notice the angle "tickmarks" btw, that means those two angles are equal, that means the triangle is an isosceles, and thus both of those sides are equal, so, if one is 50', the other is also 50'.
bear in mind that 100/10 is 10, however, we have to include the very first post, which is not spaced away 10' from anywhere, is simply touching the barn wall. So the total is 10 spaced 10' from each other plus the starting post which is touching the barnwall. And you can start doing the counting from either side A or B and you'd get 11 total.
Notice the angle "tickmarks" btw, that means those two angles are equal, that means the triangle is an isosceles, and thus both of those sides are equal, so, if one is 50', the other is also 50'.
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Answer:
The coordinates of the explosion is (3300, -2750)
Step-by-step explanation:
I have plot the points and attached to thus answer for easy understanding.
Now, from the question, since station A is the first to hear the explosion, we'll make it the foci of the parabola in the graph I attached and it will be horizontal since the distance between station C and A is much more than that between station B and A. Thus, the reason why station C will have to be the other foci with the hyperbola centred at the origin.
Now, sound travels at a speed of 1100 ft/s and station B is located 1100 ft from station A. Thus, the explosion would likely have occurred at a point on the line x = 3300ft . Since station A is 3300ft from centre C = 3300,hence C² = 3300² = 10,890,000. Since it takes 4 seconds longer for the sound to reach station C than A, the sound has traveled 4(1100)= 4400 ft.
Thus, 4400 = d1 = d2 = 2a
So,2a = 4400 and so, a =2200
a² = 2200² = 4,840,000 where d1 is the distance from station C to the explosion and d2 is the distance from station A to the explosion. To find b², let's use the equation ;
c² = a² + b² and so; b² = c² - a² = 10,890,000 - 4,840,000 = 6,050,000
Equation of hyperbola is given as;
(x²/a²) - (y²/b²) = 1
Plugging in the values of a² and b², we obtain ;
(x²/4,840,000) - (y²/6,050,000) = 1
Since we have deduced that the explosion must occur on the line x= 3300, we'll put in 3300 for x to obtain ;
(3300²/4,840,000) - (y²/6,050,000) = 1
2.25 - 1 = (y²/6,050,000)
y² = (1.25 x 6,050,000)
y² = 7562500
y = √7562500
y = ± 2750
Due to the fact that the explosion will occur at a point further from station B than from station A, the explosion will take place in quadrant 4. Thus, we will take the negative value of y which is - 2750.
So explosion will occur at the coordinate (3300, -2750)
