Answer:
Probability that the diameter of a selected bearing is greater than 111 millimeters is 0.1056.
Step-by-step explanation:
We are given that the diameters of ball bearings are distributed normally. The mean diameter is 106 millimeters and the standard deviation is 4 millimeters.
<em>Firstly, Let X = diameters of ball bearings</em>
The z score probability distribution for is given by;
Z =
~ N(0,1)
where,
= mean diameter = 106 millimeters
= standard deviation = 4 millimeter
Probability that the diameter of a selected bearing is greater than 111 millimeters is given by = P(X > 111 millimeters)
P(X > 111) = P(
>
) = P(Z > 1.25) = 1 - P(Z
1.25)
= 1 - 0.89435 = 0.1056
Therefore, probability that the diameter of a selected bearing is greater than 111 millimeters is 0.1056.
Inspired by the works of Neil Dawson and Bert Flugelman, Kassidy drafts a design for a modern sculpture, the amount of steel Kassidy will need is mathematically given as
SA=16.094711 ft^2
<h3>What is the amount of steel Kassidy will need to create the sculpture if the base of the sculpture is 4-feet tall and has a 2-foot diameter.?</h3>
Generally, the equation for the surface area of a cone is mathematically given as
SA=πr(rπ+√(h^2+r^2))
Therefore
SA=πr(rπ+√(h^2+r^2))
SA=π*1(1+√(4^2+1^2))
SA=16.094711 ft^2
In conclusion, the amount of steel Kassidy will need is
SA=16.094711 ft^2
Read more about surface area
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Answer:
A
Step-by-step explanation: