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Ilya [14]
3 years ago
14

DE is the midpoint mid segment of ABC . How would i determine the value of X

Mathematics
2 answers:
mihalych1998 [28]3 years ago
8 0
I believe x is half of 126
sladkih [1.3K]3 years ago
4 0
Because DE is half of BC, x would be half of 126.

126 / 2 = 63

Therefore, x = 63.
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5 0
3 years ago
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Simplify.<br><br> 1/4 (1 - 2/3)² + 1/3.<br><br> The answer must be a simplified fraction.
loris [4]

Answer:

\large\boxed{\dfrac{13}{36}}

Step-by-step explanation:

Use PEMDAS:

P Parentheses first

E Exponents (ie Powers and Square Roots, etc.)

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AS Addition and Subtraction (left-to-right)

---------------------------------------------------------------------------

\dfrac{1}{4}\left(1-\dfrac{2}{3}\right)^2+\dfrac{1}{3}=\dfrac{1}{4}\left(\dfrac{3}{3}-\dfrac{2}{3}\right)^2+\dfrac{1}{3}=\dfrac{1}{4}\left(\dfrac{3-2}{3}\right)^2+\dfrac{1}{3}\\\\=\dfrac{1}{4}\left(\dfrac{1}{3}\right)^2+\dfrac{1}{3}=\dfrac{1}{4}\cdot\dfrac{1^2}{3^2}+\dfrac{1}{3}=\dfrac{1}{4}\cdot\dfrac{1}{9}+\dfrac{1}{3}=\dfrac{1}{36}+\dfrac{1}{3}\qquad(*)\\\\\text{the common denominator is}\ 36.\\\\36=3\cdot12\to\dfrac{1}{3}=\dfrac{1\cdot12}{3\cdot12}=\dfrac{12}{36}\\\\(*)\qquad=\dfrac{1}{36}+\dfrac{12}{36}=\dfrac{1+12}{36}=\dfrac{13}{36}

4 0
3 years ago
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bija089 [108]
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7 0
3 years ago
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den301095 [7]

<h2><u>Answer</u><u> </u>:)</h2>

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\\\\\\

<u>Therefore</u><u> </u>

  • \sf{Option~ D ~is ~correct    }

\sf{   }

\sf{   }

\sf{   }

\sf{   } \sf{   } \sf{   } \sf{   } \sf{   }

6 0
3 years ago
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