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Stella [2.4K]
3 years ago
10

These equations take their y-values from the set (4, 5, 6, 7, 8). Arrange the equations in decreasing order of the values of y t

hat make them true.
4y + (y - 1) = 29
4y = y + 1 = 13
(2y + 3) - 4 = 9​
Mathematics
2 answers:
arsen [322]3 years ago
5 0

Answer:

in order acb  

Step-by-step explanation:

Advocard [28]3 years ago
3 0

9514 1404 393

Answer:

  a, c, b

Step-by-step explanation:

Collect terms, subtract the constant, divide by the y-coefficient.

(a) 4y + (y - 1) = 29   ⇒   y = 6

(c) (2y + 3) - 4 = 9​   ⇒   y = 5

(b) 4y - y + 1 = 13   ⇒   y = 4 . . . . . this equation is not what you have written

__

<em>Additional comment</em>

The second equation suffers from a typo, so your answer may vary.

You might be interested in
What is the solution to <br> x+y=3<br> and<br> -x+2y=6
frosja888 [35]
There are the solutions for x+y=3 and they are
(0,3) (2,1) and (1,2)
and for -x+2y=6 is
(0,3) (2,4) and (1 7/4)
hope this helps
7 0
3 years ago
Which equation has the solution x = 3?
arsen [322]
Well, let's first solve each equation:

1.) -4x + 6 - 3x = 12 - 2x - 3x

To start, combine each like-term on each side of the equal sign (The numbers with variables in-common // the numbers alike on the same side of the equal sign):

-7x + 6 = 12 - 5x

Now, we get the two terms with variables attached to them, on the same side, so, we do the opposite of subtraction, which is, addition:

-7x + 6 = 12 - 5x
+5x +5x
_____________
-2x + 6 = 12

Next, you do the opposite of addition, which is, subtraction, and, subtract 6 from both sides:

-2x + 6 = 12
-6 -6
____________
-2x = 6

Finally, divide by -2 on each side, to find out what the value of 'x' is:

-2x = 6
÷-2 ÷-2
________
x = -3

So, the answer is not 'A.'
_________________________________________

Now, we test out the rest of the equations, the exact same way:

2.) 4x + 6 + 3x = 12 + 2x + 3x

Combine your like-terms, on each side of the equal sign:

7x + 6 = 12 + 5x

Now, get both terms, with the variable, 'x,' to the same side, and, to do that, do the opposite of addition, which is, subtraction:

7x + 6 = 12 + 5x
-5x -5x
______________
2x + 6 = 12

Next, subtract 6 from both sides:

2x + 6 = 12
-6 -6
__________
2x = 6

Finally, divide by 2, on both sides:

2x = 6
÷2 ÷2
__________
x = 3

So, the answer is 'B.'
_________________________________________

3.) 4x + 6 - 3x = 12 - 2x - 3x

Again, we combine the like-terms, on both sides of the equal sign:

x + 6 = 12 - 5x

Now, we get both terms with the variable 'x,' to the same side, and, the opposite of subtraction, is addition, so, we're going to add 5x to both sides:

x + 6 = 12 - 5x
+ 5x + 5x
______________
6x + 6 = 12

Now, we subtract 6 from each side, because, the opposite of addition, is subtraction:

6x + 6 = 12
- 6 - 6
_____________
6x = 6

Now, divide by 6, on both sides:

6x = 6
÷ 6 ÷ 6
_____________
x = 1

So, the answer is not 'C.'
_________________________________________

4.) 4x + 6 - 3x = 12x + 2x + 3x

First, we combine the like-terms:

x + 6 = 17x

Next, we get both terms, with the variable, 'x,' to the same side:

x + 6 = 17x
-x -x
_____________
6 = 16x

Now, divide by 16, on both sides:

X = 3/8

So, 'D,' is not the answer.
_______________________

The answer is, 'B.'

I hope this helps!
8 0
3 years ago
Im very confused with this question dose anyone know how to do it? <br> 3.015 x 10^-7
AlexFokin [52]

Answer:

3.015e-7

Hope it helps!

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
The recursive rule for a sequence is shown.
aleksandr82 [10.1K]
Given that the recursive formula is:
an=an-1+7
first term is
a1=17
the second term will be:
a2=a(2-1)+7
a2=a1+7
a2=17+7
a2=24
To evaluate for the explicit formula we use the formula:
an=a+d(n-1)
where
a=first term
d=common difference
from the calculations above:
d=24-17=7
thus the explicit formula will be:
an=17+7(n-1)
an=17+7n-7
an=7n+17-7
an=7n+10

Answer: B] an=7n+10

4 0
4 years ago
I need help with this
natali 33 [55]

Answer:

D

Step-by-step explanation:

r =  \sqrt{ {(5 - 2)}^{2} +  {(6 - 2)}^{2}  }

3 0
3 years ago
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