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aksik [14]
3 years ago
10

At an amusement park there is a ride in which cylindrically shaped chambers spin around a central axis. People sit in seats faci

ng the axis, their backs against the outer wall. At one instant the outer wall moves at a speed of 3.28 m/s, and an 84.4-kg person feels a 488-N force pressing against his back. What is the radius of a chamber?
Physics
1 answer:
siniylev [52]3 years ago
8 0

Answer:

r = 1.86 m

Explanation:

Here the force due to wall of the cylinder is towards the axis of the cylinder

This force will act as centripetal force for the people sit inside the chamber

now we will have

F_c = \frac{mv^2}{R}

now we will have

F_c = 488 N

m = 84.4 kg

v = 3.28 m/s

now we have

488 = \frac{84.4(3.28)^2}{r}

now we have

r = 1.86 m

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