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4 years ago

The unit for energy is the

Physics

1 answer:

nikitadnepr [17]4 years ago

4 0

Explanation:

Joule (J) is the MKS unit of energy, equal to the force of one Newton acting through one meter.

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One positve and one negative charhe jave a force of -5. 00 N between them. If the force changed to -170 N , by what factor did t

stepladder [879]

Answer:

The distance is shortenend by factor .1715

Explanation:

5 n = 1/r^2

sqrt (1/5) = r

170 n = 1 / ( x sqrt(1/5))^2

(xsqrt 1/5)^2 = 1/170

x sqrt 1/5 = .076696

x = .1715

5 0

2 years ago

What style of art represents people or objects exactly as they appear in life?

Nady [450]

The answer is realism.

4 0

3 years ago

Read 2 more answers

A pendulum has 141 J of potential energy at the highest point of its swing. How much kinetic energy will it have at the bottom o

Lubov Fominskaja [6]

Assume that energy losses (due to aerodynamic resistance or bearing friction are negligible).

At the highest point, the pendulum has its maximum potential energy (PE) and zero kinetic energy (KE). The total energy is equal to the PE = 141 J.

At the lowest point, the pendulum has its maximum KE, and zero PE. The total energy is equal to the KE.

Because energy is preserved, therefore
KE at the lowest point = PE at the highest point = 141 J.

Answer: 141 J

3 0

3 years ago

12*3a car is stopped at a traffic light. it then travels along a straight road so that its distance from the light is given by w

Digiron [165]

Missing parts in the text of the exercise:
- The distance from the traffic light is given by $x(t) = bt^2 -ct^3$ , where $b=2.4 m/s^2$ and $c=0.13 m/s^3$

Solution:

part a) calculate the average velocity of the car for the time interval t=0 to t=8.0 s
- The average velocity is given by the ratio between the distance covered in the time interval:
 $v_{ave} = \frac{x(8.0 s)-x(0 s)}{8.0 s-0 s}$
x(0 s), the distance covered after t=0 s, is zero, while the distance after t=8.0 s is
$x(8.0 s)=b(8 s)^2-c(8 s)^3 = (2.4 m/s^2)(8 s)^2 -(0.13 m/s^3)(8 s)^3=$
$=87.04 m$
Therefore, the average velocity is
$v_{ave}= \frac{x(8.0 s)-x(0)}{8.0s-0}= \frac{87.04 m}{8.0s}= 10.88 m/s$

part b) calculate the instantaneous velocity of the car at t=0, t=4.0 s and t=8.0 s
- The instantaneous velocity can be found by performing the derivation of x(t):
 $v(t) = \frac{dx(t)}{dt}=2bt-3ct^2$
So now we just have to substitute t=0, t=4 s and t=8 s:
- t=0: v(0)=0
- t=4 s: $v(4.0 s)=2(2.4 m/s^2)(4.0 s)-3(0.13 m/s^2)(4.0s)^2=12.96 m/s$
- t=8 s: $v(8.0 s)=2(2.4 m/s^2)(8.0 s)-3(0.13 m/s^2)(8.0s)^2=13.44 m/s$

part c) how long after starting from rest is the car again at rest?
- To solve this part we must find the value of t for which v(t)=0, so:
 $2bt-3ct^2=0$
$t(2b-3ct)=0$
The first solution is t=0 s, which corresponds to the beginning of the motion, so we are not interested in this value. The second solution is
 $t= \frac{2b}{3c}= \frac{2\cdot 2.4 m/s^2}{3 \cdot 0.13 m/s^3}=12.31 s$
and this is the time at which the car is at rest again.

8 0

4 years ago

an unbalanced force of 965 N causes an object to accelerate at 54.5 m/s^2. what is the mass of the object

Andru [333]

Answer:

$F=ma \\ 965 = m(54.5) \\ m = \frac{965}{54.5} \\ m = 17.7kg$

8 0

2 years ago

The unit for energy is the​

The unit for energy is the