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Agata [3.3K]
3 years ago
11

For a given initial velocity, how does the time td it takes to stop on dry snow differ from the time tw it takes to stop on wet

snow
Physics
1 answer:
salantis [7]3 years ago
7 0

let the friction coefficient on dry ice and wet ice is different and given as

\mu_d = on dry ice

\mu_w = on wet ice

now by friction force formula we can say

F_f = -\mu mg

so the deceleration due to friction force is given as

a = -\mu g

now the deceleration due to friction force on both surface is given as

a_1 = -\mu_d * g

a_2 = -\mu_w * g

now the time to stop the two blocks can be calculated by kinematics

v_f - v_i = a t

0 - v_0 = -\mu_d * g * t_d

t_d = \frac{v_0}{\mu_d* g}

also for other block on wet ice we can say similarly

t_w = \frac{v_0}{\mu_w*g}

now the ratio of two time on two surfaces is given as

\frac{t_d}{t_w} = \frac{\mu_w}{\mu_d}

so this is the ratio of time on two surfaces

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