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3 years ago

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What are the multiples of 44?

2 answers:

denis-greek [22]3 years ago

3 0

The multiples of 44 are 44, 88, 132, 176, 220, and so on. Each number that comes after increases by 44.

ella [17]3 years ago

3 0

<span>In Mathematics, multiple refers to the product of an integer and quantity.
Now, we need to find the multiple of given number which is 44.
=></span><span>44, 88, 132, 176, 220, 264, 308, 352, 396, 440, 484, 528, 572, 616, 660, 704, 748, 792, 836, 880, 924, 968, 1012, 1056, 1100, 1144, 1188, 1232, 1276, 1320, 1364, 1408, 1452, 1496, 1540, 1584, 1628, 1672, 1716, 1760, 1804, 1848, 1892, 1936, 1980, 2024, 2068, 2112, 2156</span>

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F(x) = x2<br> What is f(x) + f(x) + f(x)?

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joja [24]

Part (1) : The solution is $729$

Part (2): The solution is $\frac{1}{16 x^{8}}$

Part (3): The solution is $\frac{2 x^{2}}{3 y z^{7}}$

Explanation:

Part (1): The expression is $3^{2} \cdot3^{4}$

Applying the exponent rule, $a^{b} \cdot a^{c}=a^{b+c}$ , we get,

$3^{2} \cdot 3^{4}=3^{2+4}$

Adding the exponent, we get,

$3^{2} \cdot3^{4}=3^6=729$

Thus, the simplified value of the expression is $729$

Part (2): The expression is $\left(2 x^{2}\right)^{-4}$

Applying the exponent rule, $a^{-b}=\frac{1}{a^{b}}$ , we have,

$\left(2 x^{2}\right)^{-4}=\frac{1}{\left(2 x^{2}\right)^{4}}$

Simplifying the expression, we have,

$\frac{1}{2^4x^8}$

Thus, we have,

$\frac{1}{16 x^{8}}$

Thus, the value of the expression is $\frac{1}{16 x^{8}}$

Part (3): The expression is $\frac{2 x^{4} y^{-4} z^{-3}}{3 x^{2} y^{-3} z^{4}}$

Applying the exponent rule, $\frac{x^{a}}{x^{b}}=x^{a-b}$ , we have,

$\frac{2x^{4-2}y^{-4+3}z^{-3-4}}{3}$

Adding the powers, we get,

$\frac{2x^{2}y^{-1}z^{-7}}{3}$

Applying the exponent rule, $a^{-b}=\frac{1}{a^{b}}$ , we have,

$\frac{2 x^{2}}{3 y z^{7}}$

Thus, the value of the expression is $\frac{2 x^{2}}{3 y z^{7}}$

8 0

3 years ago