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2 years ago

Y=-(x-3)^2 +8 in standard form

Mathematics

1 answer:

Zolol [24]2 years ago

5 0

Answer:

y=−2(x−)x+8

i believe this is it im not sure since ^2

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Read 2 more answers

Point M is the midpoint of segment AB.<br> AM=3x+40 and MB=x^2. Find x and AB

Nina [5.8K]

$\text{Hello there! :)}$

$x = 8\\\\AB = 128 \text{ units}$

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$\text{Since Point M is the midpoint of AB, then:}\\\\AM = MB\\\\$

$\text{Set the two equations equal to each other:}\\\\3x + 40 = x^{2} \\\\$

$\text{Move all terms over to one side to simplify more easily:}\\\\0 = x^{2} - 3x - 40$

$\text{Factor by finding numbers that sum up to -3 and multiply into -40:}\\\\0 = (x - 8)(x + 5)\\\\x = -5, 8$

$\text{The length of a segment cannot be negative, so choose the positive solution:}\\\\x = 8$

$\text{Substitute in this value of x into either AM or MB to solve for AB:}$

$AB = 2(MB)\\\\AB = 2(x^{2} )\\\\AB = 2(8^{2})\\ \\AB = 2(64)\\\\AB = 128 \text{ units}$

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3 years ago