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MaRussiya [10]
3 years ago
11

Are the area of a square and the length of its side directly proportional quantities?

Mathematics
1 answer:
Angelina_Jolie [31]3 years ago
7 0

Answer:

Yes they are directly proportional quantities.

Step-by-step explanation:

We find the area of a square by;

A = length squared or (L)² , where 'L' stands for length and 'A' stands for area.

So Area = L²

Assume the length is a units and increase the length by 2 units

The initial area before increasing the length is a²

After increasing the length, the area becomes: (a + 2)² = a² + 4a + 4

Now we subtract the initial area from the final area and get;

(a² + 4a + 4) - a² = 4a + 4

So the new area increases by 4a + 4 units.

Hence, the area increases as the length increases implying that the area of a square is directly proportional to its length.

We denote this proportionality as;

A ∝ L

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233568

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b

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The n term of a geometric sequence is denoted by Tn and the sum of the first n terms is denoted by Sn.Given T6-T4=5/2 and S5-S3=
Leno4ka [110]
1 step: S_{5}=T_{1}+T_{2}+T_{3}+T_{4}+T_{5}, S_{3}=T_{1}+T_{2}+T_{3}, then
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2 step: T_{n}=T_{1}*q^{n-1}, then 
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and \left \{ {{T_{6}-T_{4}= \frac{5}{2} } \atop {T_{5}+T_{4}=5}} \right. will have form \left \{ {{T_1*q^{5}-T_{1}*q^{3}= \frac{5}{2} } \atop {T_{1}*q^{4}+T_{1}*q^{3}=5} \right..

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5 0
3 years ago
1 A lawnmower that regularly sells for $200 is on sale for $85. Find the % of change that the price was decreased by ??? percent
Airida [17]

Answer:

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The price changed by 92.5 %

4 0
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