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Digiron [165]
3 years ago
7

Can someone plz help!!!!!

Mathematics
1 answer:
kakasveta [241]3 years ago
5 0

Answer:

17. 15

18. 8(this one I'm not sure tho what does the right one say)

19. 32

20. 5

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Please can someone help me with my maths? I’m so confused
Blababa [14]
The y intercept is 0.5 because thats where the line starts.
the slope/gradient of the line is 1.5.
this would be written in the form: y=1.5x+0.5
5 0
3 years ago
What number is four times as many as 25
Nana76 [90]

Answer:

100

Step-by-step explanation:

4 x 25 = 100

7 0
3 years ago
Can someone please help me
Genrish500 [490]

Answer:

c

Step-by-step explanation:

come on ! you can literally see that in the chart.

how many parts of the gray 3/8 are covered by the gray 1/4 ?

2 parts = 2/8 are clearly covered by 1/4.

2/8 is what part of 3/8 ?

it is the same question as "2 is what part of 3" ?

is 2 a quarter (1/4) of 3 ? no, 1/4×3 = 3/4 and not 2.

is 2 one third (1/3) of 3 ? no, 1/3 of 3 = 1/3×3 = 1 and not 2.

is 2 two thirds (2/3) of 3 ? ah, 2/3 × 3 = 2. that is correct !

is 2 three quarters (3/4) of 3 ? no, 3/4×3 = 9/4 and not 2.

once you have the same denominator, you can easily compare the numerators and ignore the denominators for such problems.

8 0
3 years ago
Find the y and x intercept 6x-8y=48
Crank

6x-8y=48


to find the x intercept  set y=0

6x - 8*0 = 48

6x = 48

divide by 6 on each side

x =48/6

x=8

 (8,0)


to find the y intercept  set x=0

6(0) - 8y = 48

0 - 8y = 48

-8y = 48

divide by -8 on each side

y = -6

(0,-8)



8 0
3 years ago
Let f be a differentiable function such that f(0) = -5 and f'(x) is less than or equal to 3 for all x. Of the following, which i
stepladder [879]
E) 2 
 Remember that the first derivative of a function is the slope of the function at any specified point. We've been told that f(0) = -5 and that f'(x) is always less than or equal to 3. So let's look at the available options and see what the average slope would have to be in order to get the specified value of f(2).
 A) -10: (-10 - -5)/(2 - 0) = -5/2 = -2.5
 B) -5: (-5 - -5)/(2 - 0) = 0/2 = 0
 C) 0: (0 - -5)/(2 - 0) = 5/2 = 2.5
 D) 1: (1 - -5)/(2 - 0) = 6/2 = 3
 E) 2: (2 - -5)/(2 - 0) = 7/2 = 3.5 
 Now taking into consideration the mean value theorem, the value of the function f'(x) has to have the value equal to the average slope between the two points at at least one point between the two given values. For options A, B, C, and D it's possible for f'(x) to return values that make that slope possible. However, for option E, the mean value theorem indicates that f'(x) has to have the value of 3.5 for at least 1 point between x=0 and x=2. And since we've been told that f'(x) is less than or equal to 3 for all possible values of x, that is in conflict and f(2) can not have the value of 2.
3 0
3 years ago
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