2 years ago

2 sides equations

Mathematics

1 answer:

lapo4ka [179]2 years ago

6 0

Answer:

15x-8x-5x=48

3x=48

or X=16

4=4y+2y

or 4= 6y

or 4/6=y

or y=2/3

4-5x= 3x

or 4=5x+3x

or 4=8x

or 4/8=X

or X=2

2x=2x-5+8

or,2x= 2x-13

or 2x+2x=13

or 4x=13

or X= 13/4

or X =3.25

4y=4y+9-9

or 4y=4y+0

or 4y-4y=0

or 0=0

You might be interested in

What is the domain of square root x+6 substract 7

creativ13 [48]

Y=√(x+6) - 7

constraint: x+6> or = 0
or x> 0r = -6
RANGE = x∈R/ x > or = 0

3 0

2 years ago

(4 x 10) + (2 x 104)<br> Give your answer in standard form

Goshia [24]

Answer: =248x

Step-by-step explanation: Hope this help :D

Let's simplify step-by-step.

4x(10)+2x(104)

=40x+208x

Combine Like Terms:

=40x+208x

=(40x+208x)

=248x

7 0

2 years ago

A triangle has side lengths of 6x + 8 cm, 8x - 3y cm, and 9 - 5y cm.

elena55 [62]

Answer:

thanks lol

Step-by-step explanation:

5 0

2 years ago

Find the missing coefficent. (5d - 7)(5d - 6) = 25d2 + d + 42

Tcecarenko [31]

25d^2-30d-35d+42=25d^2-65d+42.

5 0

2 years ago

Read 2 more answers

The arithmetic sequence a; is defined by the formula:

Morgarella [4.7K]

Answer:

The sum of the first 650 terms of the given arithmetic sequence is 2,322,775

Step-by-step explanation:

The first term here is 4

while the nth term would be ai = a(i-1) + 11

Kindly note that i and 1 are subscript of a

Mathematically, the sum of n terms of an arithmetic sequence can be calculated using the formula

Sn = n/2[2a + (n-1)d)

Here, our n is 650, a is 4, d is the difference between two successive terms which is 11.

Plugging these values, we have

Sn = (650/2) (2(4) + (650-1)11)

Sn = 325(8 + 7,139)

Sn = 325(7,147)

Sn = 2,322,775

6 0

2 years ago