3/5 of $40 restraunt bill

If the probability of an events is 2/7 what must be the probability of its compliments

monitta

Answer:

The probability of its compliments = 0.7143 = 5/7

Step-by-step explanation:

The probability of an events = P= 2/7 = 0.2857

The probability of its compliments = 1-p = 1-0.2857 = 0.7143 = 5/7

6 0

3 years ago

What number is 40% of 720

pentagon [3]

Answer:

288

Step-by-step explanation:

Hope it helps :>

8 0

3 years ago

Read 2 more answers

ΔABC undergoes a translation to become ΔA'B'C'. Are the triangles congruent, similar, neither or both? Explain.

Alenkasestr [34]

I can’t solve without a graph.

6 0

2 years ago

the expression 15 a + 12 C is the cost in dollars of a admission at an amusement park for a adults and see children find the tot

Blizzard [7]

Answer:

$195

Step-by-step explanation:

15a + 12c

5 adults and 10 children means a = 5 and c = 10

15a + 12c = 15(5) + 12(10) = 75 + 120 = 195

5 0

3 years ago

Giving 100 points.

Nitella [24]

Answer:

1. Cost per customer: 10 + x

Average number of customers: 16 - 2x

$\textsf{2.} \quad -2x^2-4x+160\geq 130$

3. $10, $11, $12 and $13

Step-by-step explanation:

Given information:

$10 = cost of buffet per customer
16 customers choose the buffet per hour
Every $1 increase in the cost of the buffet = loss of 2 customers per hour
$130 = minimum revenue needed per hour

Let x = the number of $1 increases in the cost of the buffet

Part 1

Cost per customer: 10 + x

Average number of customers: 16 - 2x

Part 2

The cost per customer multiplied by the number of customers needs to be at least $130. Therefore, we can use the expressions found in part 1 to write the inequality:

$(10 + x)(16 - 2x)\geq 130$

$\implies 160-20x+16x-2x^2\geq 130$

$\implies -2x^2-4x+160\geq 130$

Part 3

To determine the possible buffet prices that Noah could charge and still maintain the restaurant owner's revenue requirements, solve the inequality:

$\implies -2x^2-4x+160\geq 130$

$\implies -2x^2-4x+30\geq 0$

$\implies -2(x^2+2x-15)\geq 0$

$\implies x^2+2x-15\leq 0$

$\implies (x-3)(x+5)\leq 0$

Find the roots by equating to zero:

$\implies (x-3)(x+5)=0$

$x-3=0 \implies x=3$

$x+5=0 \implies x=-5$

Therefore, the roots are x = 3 and x = -5.

Test the roots by choosing a value between the roots and substituting it into the original inequality:

$\textsf{At }x=2: \quad -2(2)^2-4(2)+160=144$

As 144 ≥ 130, the solution to the inequality is between the roots:

-5 ≤ x ≤ 3

To find the range of possible buffet prices Noah could charge and still maintain a minimum revenue of $130, substitute x = 0 and x = 3 into the expression for "cost per customer.

[Please note that we cannot use the negative values of the possible values of x since the question only tells us information about the change in average customers per hour considering an increase in cost. It does not confirm that if the cost is reduced (less than $10) the number of customers increases per hour.]

Cost per customer:

$x =0 \implies 10 + 0=\$10$

$x=3 \implies 10+3=\$13$

Therefore, the possible buffet prices Noah could charge are:

$10, $11, $12 and $13.

8 0

2 years ago