Question

The mosquito Aedes aegypti has a diploid number of 6 chromosomes. How many DNA molecules and Chromosomes are found per cell when this cell is progressing through the following stages: After Anaphase II of Meiosis the cell has-DNA molecules and- Chromosomes O 6,6 ○ 63 O 12,6 12, 12

Answer 1

Answer:

Option C, 12, 6

Explanation:

The number of chromosome and DNA molecule are interpreted through the number of functional centromere and chromatids respectively at each phase of the cell division.  

However, the DNA number only changes in the S phase of the cell division as replication occurs in this phase only.  

Hence, after meiosis I two daughter cells will be formed with half the chromosome number i.e 3 and number of DNA is equal to 12.  

Now, till metaphase II no change occurs. Now at anaphase II DNA remains same while the chromosome number increases to 6

Thus, the correct answer is option C

Answer 2

Answer:

6 DNA molecules and 6 chromosomes.

Explanation:

Meiosis is the process of the cell division in which the chromosome number reduces to half as compared with the parent DNA. The cells undergoes the reduction division.

In meiosis the cell divides two times to produce four haploid daughter cells. A single chromosome has 2 DNA molecules. If the chromosome number in diploid cell is 6, then after the anaphase II the chromatid separation occurs and each chromatid is considered as a single chromosomes. The cells at anaphase II contains 6 chromosomes. The number of DNA molecules will be 6.

Thus, the correct answer is option (1).