Answer:
Step-by-step explanation:
A rancher wants to enclose a rectangular field with 220 ft of fencing.
One side is a river and will not require a fence.
What is the maximum area that can be enclosed?
:
The field requires only 3 sides of fence, therefore
L + 2W = 220
L = (220-2W); we can use this for substitution in the Area equation
:
Area
A = L*W
replace L with (220-2W)
A = W(220-2W)
A = -2W^2 + 220W
A quadratic equation, max A occurs at the axis of symmetry, x = -b/(2a)
In this equation
W = %28-220%29%2F%282%2A-2%29
W = 55 ft is the width for max area
:
Find the max area
A = -2(55^2) + 220(55)
A = -2(3025) + 12100
A = 6050 sq/ft is the max area
:
:
Confirm this with the dimensions calculated; 110 * 55 = 6050
The correct answer is 1 5/6
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Answer:</u></h2>
n²-25
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Explanation:</u></h2>
Expand the polynomial using the FOIL method. (A handy way to remember how to multiply two binomials. It stands for "First, Outer, Inner, Last")
Step-by-step explanation:
Below is an attachment containing the solution.
